Answer:
I think the answer would be +15.
Step-by-step explanation:
Answer:
1. 81.0
2. I`m trying to figure that out now I will give answers when I can
Step-by-step explanation:
45 = 3x3x5
Or you could simplify it to 3^2x5
Answer:
A sample size of 6755 or higher would be appropriate.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error M is given by:

90% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
52% of Independents in the sample opposed the public option.
This means that 
If we wanted to estimate this number to within 1% with 90% confidence, what would be an appropriate sample size?
Sample size of size n or higher when
. So







A sample size of 6755 or higher would be appropriate.
Answer:
since there are 30 students as a whole and 20 boys make up part of the class, you can assume that there are 10 girls in the class. since the mean mark for boys is 62 I think the mean mark for girls would be 8%
Step-by-step explanation: