Mark, Anthony, and Derek, are going on a road trip and will take turns driving the car. They need to decide who will drive first
.
Which method assures that each of the three friends has a fair chance of being selected to drive first?
O A. "Using a random number generator, generate an integer. If the number is negative, Mark drives first. If the number is positive,
Anthony drives first. If the number is 0, Derek drives first.
OB.
Flip two fair coins. If both coins land on tails, Mark drives first. If both coins land on heads, Anthony drives first. If one coin
lands on tails and the other lands on heads, Derek drives first.
O C. Spin a spinner with four equal-sized sections labeled A, B, C, and D. If the spinner lands on A, Mark drives first. If the spinner
lands on B, Anthony drives first. If the spinner lands on C, Derek drives first. If the spinner lands on D, Mark drives first.
OD. Roll an ordinary die. If the die lands on 1 or 4, Mark drives first. If the die lands on 2 or 5, Anthony drives first. If the die lands
on 3 or 6, Derek drives first.
Which method assures that each of the three friends has a fair chance of being selected to drive first?
O A. "Using a random number generator, generate an integer. If the number is negative, Mark drives first. If the number is positive,
Anthony drives first. If the number is 0, Derek drives first.
OB.
Flip two fair coins. If both coins land on tails, Mark drives first. If both coins land on heads, Anthony drives first. If one coin
lands on tails and the other lands on heads, Derek drives first.
O C. Spin a spinner with four equal-sized sections labeled A, B, C, and D. If the spinner lands on A, Mark drives first. If the spinner
lands on B, Anthony drives first. If the spinner lands on C, Derek drives first. If the spinner lands on D, Mark drives first.
OD. Roll an ordinary die. If the die lands on 1 or 4, Mark drives first. If the die lands on 2 or 5, Anthony drives first. If the die lands
on 3 or 6, Derek drives first.
1 answer:
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Equation of Anjeli is true.
<u>Step-by-step explanation:</u>
Triangle ABC right angle at C such that
Considering AB = c as (Hypotenuse), AC = b as (Longer leg), BC = a as (Shorter leg)
Proof:
(a+b)² = c²+ 4(1/2) ab
In the Triangle ABC, by Pythagoras theorem, Plugin the values we will get,
Hypotenuse² = longer leg² + shorter leg²
AB² = AC²+ BC²
c² = b²+ a² ------ q
(a+ b)² can be written using the identity as,
(a+ b)²= a² + 2ab + b² ----LHS
Plugin the above identity in the eq. q we will get,
c²+ 2ab = c² + (4/2) ab --- RHS
So LHS = RHS.
Hence proved.
