Answer:
a) x = -10
b) x = 7
Step-by-step explanation:
a)
2(x + 3) = x - 4
2x + 6 = x - 4
2x - x = -4 - 6
x = -10
b)
4(5x - 2) = 2(9x + 3)
20x - 8 = 18x + 6
20x - 18x = 6 + 8
2x = 14
x = 7
Answer:
Dividends = $105000
So option (c) will be correct answer
Step-by-step explanation:
We have given that Retained earning on 12/31/18 is $475000
And retained earning on 12/31/18 is $445000
Net income = $135000
Change in retained income = $475000-$445000 = $30000
We have to find dividends
We know that dividends is given by
Dividends = net income - change in retained income = $135000-$30000 = $105000
So option (c) will be correct answer
Answer:
x = 5
Step-by-step explanation:
To find the value of x make sure to get it on one side
First subtract 3x from each side. This makes the equation now
3x + 2 = -8 + 25
Now see what 25 subtract by 8 is (17)
3x + 2 = 17
Next subtract 2 from both sides
3x = 15
Lastly, divide 15 by 3, making x equal 5
x = 5
Answer:
The number of Carmel muffins is 8 and the number of lemon muffins is 12.
Step-by-step explanation:
Melvin Marshall bought a total of 20 Muffins . Some were camel-glazed muffins and some were lemon. The Carmel muffins cost $3 each while the lemons cost $2.5 . The number of carmel muffins and lemon muffins can be calculated as follows
total number of muffin = 20
Let
a = number of carmel - glazed muffins
b = number of lemon muffins
a + b = 20.............(i)
The total cost
3a + 2.50b = 54................(ii)
Combine the equations
a + b = 20.............(i)
3a + 2.50b = 54................(ii)
a = 20 - b
insert the value of a in equation (ii)
3(20 - b) + 2.50b = 54
60 - 3b + 2.50b = 54
60 - 54 = 0.5b
0.5b = 6
divide both sides by 0.5
b = 6/0.5
b = 12
Insert the value of b in equation (i)
a + b = 20.............(i)
a + 12 = 20
a = 20 - 12
a = 8
The number of Carmel muffins is 8 and the number of lemon muffins is 12.
Answer: The mean of this distribution = 61.95
The standard deviation of this sampling distribution (i.e., the standard error= 0.048
Step-by-step explanation:
Given : Data from the U.S. Department of Education indicates that 59% of business graduate students from private universities had student loans.
i.e. proportion of business graduate students from private universities had student loans : p=0.59
sample size : n=105
Then , the mean of the distribution is given by :-

∴The mean of this distribution = 61.95
Then standard deviation of this sampling distribution is given by :-

∴The standard deviation of this sampling distribution (i.e., the standard error= 0.048