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pychu [463]
4 years ago
9

A parent pushes a single child on a swing. Suppose two children now sit on the same swing, and the parent pushes with the same f

orce.
According to Newton's Second Law of Motion, what is the result?


A. mass decreases, acceleration increases

B. mass decreases, acceleration decreases

C. mass increases, acceleration increases

D. mass increases, acceleration decreases
Mathematics
2 answers:
yawa3891 [41]4 years ago
4 0

the answer will be D.

Kryger [21]4 years ago
4 0

Answer:

D

Step-by-step explanation:

According to Newton's second law of motion, mass is inversely proportional to acceleration. As mass increases, acceleration decreases and the opposite.

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Lines l and m are parallel. Parallel lines l and m are intersected by lines s and t. At the intersection of lines l, s, and t, c
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Answer:

All of them are true except for the second one.

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3 years ago
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emmainna [20.7K]

Answer:

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It's a pythagorean triple

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Find the square. (1/4A + 1/4B)^2<br><br> a) 1/16A^2 + 1/8AB + 1/16B^2<br> b) 1/4A^2 + 1/8AB + 1/4B^2
alisha [4.7K]

(a + b)^2 = a^2 + 2ab + b^2

(\dfrac{1}{4}A + \dfrac{1}{4}B)^2 =

= \dfrac{1}{16}A^2 + \dfrac{1}{8}AB + \dfrac{1}{16}B^2

Answer: A.

Another way to solve by factoring 1/4.

(\dfrac{1}{4}A + \dfrac{1}{4}B)^2 =

= [\dfrac{1}{4}(A + B)]^2

= (\dfrac{1}{4})^2(A + B)^2

= \dfrac{1}{16}(A^2 + 2AB + B^2)

= \dfrac{1}{16}A^2 + \dfrac{1}{16}2AB + \dfrac{1}{16}B)^2

= \dfrac{1}{16}A^2 + \dfrac{1}{8}AB + \dfrac{1}{16}B)^2

6 0
3 years ago
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 They spent $18 on tickets to the carnival and $36 on food.  They spent the rest of the money on g They spent $18 on tickets
Reptile [31]

Answer:

93 = g + 36 + 18

Step-by-step explanation:

8 0
3 years ago
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Vinvika [58]

Answer:

x = -15/2

Step-by-step explanation:

For this problem, we will simply use equation properties to solve for x.

2x - 5 = -20

2x - 5 + 5 = -20 + 5

2x = -15  ( Add positive 5 to both sides )

2x * (1/2) = -15 * (1/2)

x = -15/2  ( Multiply both sides by 1/2)

Hence, the solution to x is -15 / 2.

Cheers.

4 0
3 years ago
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