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2 years ago

12

Colton bounces a ball 3.268 feet infront of his feet. The path of the ball from the time it hits the ground until it lands on th

e floor is represented by

1 answer:

Otrada [13]2 years ago

5 0

here is the complete and correct question. Colton bounces a ball 3.268 feet in front of his feet. The path of

the ball from the time it hits the ground until it lands on the floor is represented by

f(x) =-4(x - 5)2 + 12

Assuming that Colton's feet are located at the origin, (0, 0), what is the maximum height of the ball (in feet)?

Answer:

12ft

step by step explanation:

This equation has been written in vertex form, and it has its vertex at (5, 12). Because the scale factor is not positive, it has a negative value, the graph for the question is going to open downward, such that the vertex,

that is the maximum height is 12 ft.

we have The equation of a parabola with vertex (h, k) to be

f(x) = a(x -h)² + k

when put in Comparison to your question function, we get that

a=-4

h=5

k=12

so the vertex (h, k) = (5, 12).

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An astronaut who weighs 85 kilograms on earth weighs 14.2 kilograms on the moon. How much would a person weigh on the moon if th

STatiana [176]

Answer:

Weight on the moon=x=15.87 kilograms

Step-by-step explanation:

This can be expressed as;

Weight on earth=Constant×Weight on moon

where;

Weight on moon=14.2 kilograms

Constant=k

Weight on Earth=85 kilograms

Replacing in the expression above;

85=14.2×k

k=(85/14.2)=5.986

If the person weighs 95 kilograms on Earth;

Weight on the earth=Constant×Weight on moon

where;

Weight on the moon=x

Constant=5.986

Weight on the earth=95 kilograms

Replacing;

95=5.986×x

x=95/5.986=15.87

Weight on the moon=x=15.87 kilograms

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2 years ago

What’s the square root of 108 a to the 7th power b to the 5th power

MissTica

Answer:

Step-by-step explanation:

Factor all the factors making up the square root.

108: 2*2*3*3*3

a^7: a*a*a*a*a*a*a

b^5:b * b * b * b * b

The rule for taking a square root of this is

For every pair, you get to take one number outside the root sign and throw the other one away.

2*3*a * a * a* b * b√(3*a * b)

6a^3b^2 * √(3*a*b)

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3 years ago

I can’t figure out how to use the zeros in the polynomial. Please explain

Temka [501]

Answer:

a) $P (x) = (x + 3) (x-1) (x-4)$

b) $P (x) = (2x + 5) (5x - 4) (x-6)$

c) $P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2$

Step-by-step explanation:

<u>For the question a *</u> you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.

This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.

Then write the polynomial in factored form.

$P (x) = (x + 3) (x-1) (x-4)$

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.

<u>For question b, do the same procedure</u>.

Degree: 3

Zeros: -5/2, 4/5, 6.

The factors are

$x = -\frac{5}{2}\\\\x +\frac{5}{2} = 0\\\\(2x +5) = 0$

---------------------------------------

$x =\frac{4}{5}\\\\x-\frac{4}{5} = 0\\\\(5x-4) = 0$

--------------------------------------

$x = 6\\\\(x-6) = 0$

--------------------------------------

$P (x) = (2x + 5) (5x - 4) (x-6)$

<u>Finally for the question c we have</u>

Degree: 5

Zeros: -3, 1, 4, -1

Multiplicity 2 in -1

$x = -3\\\\(x-3) = 0$

--------------------------------------

$x = 1\\\\(x-1) = 0$

--------------------------------------

$x = 4\\\\(x-4) = 0$

----------------------------------------

$x = -1\\\\(x + 1) = 0$

-----------------------------------------

$P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2$

8 0

2 years ago

Slove the following equation.<br>6n - 3(n + 2) + 3(7n + 1) = 0

Otrada [13]

Answer:

here is my working out to find answer, if u feel that the answer is wrong then do the reverse calculation by putting n value to the equation. hope u understood and stay safe!

6 0

2 years ago

Which expression is equivalent to (81x4y16)12 for all positive values of x and y?<br> 40.5x4y16

IrinaVladis [17]

Answer:

$(81x^4y^{16})^{\frac{1}{2}} = 9 x^2 y^8$

Step-by-step explanation:

Given

$(81x^4y^{16})^{\frac{1}{2}}$

Required

Determine an equivalent expression

Express 81 as $9^2$

$(9^2x^4y^{16})^{\frac{1}{2}}$

Apply law of indices

$9^2^{\frac{1}{2}} * x^4^{\frac{1}{2}} * y^{16}^{\frac{1}{2}}$

$9^{\frac{2*1}{2}} * x^{\frac{4*1}{2}} * y^{\frac{16*1}{2}}$

$9^{\frac{2}{2}} * x^{\frac{4}{2}} * y^{\frac{16}{2}}$

$9^1 * x^2 * y^8$

$9 * x^2 * y^8$

$9 x^2 y^8$

Hence:

$(81x^4y^{16})^{\frac{1}{2}} = 9 x^2 y^8$

4 0

2 years ago