Helppppppppppppp plzzzzz

The surface of An air hockey table has an area of 40 ft. Perimeter is 28 feet what are the dimension of the air hockey table

sukhopar [10]

Answer:

4ft and 10ft

Step-by-step explanation:

you got to figure out which 2 numbers when multipled make 40 and when added make and then multiplied by 2 make 28

5 0

2 years ago

HELPPPPPPPPPpp THIS IS HARD. find the value of x

Tanya [424]

Answer:

x = 155°

Step-by-step explanation:

The sum of the angles in any triangle = 180°

1. The triangle with the right angle and the 35° angle: We know the acute angles of a right angle sum = 90°. So 35° + what angle = 90° ; the missing angle = 90° - 35° = 55°

You have a straight angle formed with the 60° + ?° + 55° that is equal to 180°. 60° + 55° + ? = 180; 115°+ ? = 180; ? = 65°.

Now "x" is any exterior angle which tells you that it is equal to the two remote angles. The two remote angles are 65° + 90° = x° ; x = 155°

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4 0

3 years ago

Read 2 more answers

Give this problem a try and try to solve this

tia_tia [17]

Answer:

No solution

Step-by-step explanation:

Given equation is,

$\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}-\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}=0$

$\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}=\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}$

$\frac{(x+1)}{\sqrt{x}(1-x)}+\frac{(\sqrt{x}-1)}{\sqrt{x}(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}$

$\frac{(\sqrt{x}+1)(x+1)+(\sqrt{x}-1)(1-x)}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}$

$\frac{x\sqrt{x}+x+\sqrt{x}+1+\sqrt{x}-1-x\sqrt{x}+x}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}$

$\frac{2x+2\sqrt{x}}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}$

$\frac{2(\sqrt{x}+1)}{(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}$

$\frac{2}{1-x}=(\frac{4+x}{1-x})^\frac{1}{2}$ if x ≠ ±1

$(\frac{2}{1-x})^2=\frac{4+x}{1-x}$ [Squaring on both the sides of the equation]

$\frac{4}{(1-x)}=(4+x)$

4 = (1 - x)(4 + x)

4 = 4 - 4x + x - x²

0 = -3x - x²

x² + 3x = 0

x(x + 3) = 0

x = 0, -3

But both the solutions x = 0 and x = -3 are extraneous solutions, given equation has no solution.

5 0

4 years ago

Read 2 more answers

Let h(x)=xg(x), where g(x)=the inverse of f(x). Find h'(5) using the chart.....(type that in a minute) ...?

Darina [25.2K]

h(x) = x g(x)
h'(x) = x g'(x) + (1)g(x)
h'(x) = x g'(x) + g(x)

Since g(x) = f^-1(x), then
g'(x) = 1/f'(x)

h'(x) = x/f'(x) + f^-1(x)
Therefore,
h'(5) = 5/f'(5) + f^-1(5).

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

5 0

4 years ago

What is the perimeter of the regular hexagon ? <br> 3m

mr Goodwill [35]

If you are trying to ask what the perimeter is for a hexagon that has 3m sides your answer would be 18m

7 0

4 years ago