Answer:
He has 47
Step-by-step explanation:
if one guy has 50 it wold make sense to give the other 50 but since he has 53 then he must have 47
Answer:
± 60
Step-by-step explanation:
aₙ = a₁ * rⁿ⁻¹
a₇ = 30 = a₁ * r⁷⁻¹ = a₁ * r⁶ (1)
a₅ = 120 = a₁ * r⁵⁻¹ = a₁ * r⁴ (2)
(1)/(2): 30/120 = 1/4 = r²
r = ± 1/2 or ± 0.5
a₁ = a₇/r⁶ = 30/0.5⁶ = 1920
a₆ = 1920 * (± 1/2)⁶⁻¹ = 1920 * ± 1/32 = ± 60
Answer:
I think c
Step-by-step explanation:
that is what it showed on my test I am not a 100% sure.
Answer:
If the rest of the question is:
Each game is a win or a loss.
He wins three fifths of his first 40 games.
He then wins his next 12 games.
For all 52 games, work out the ratio wins : losses
Give your answer in its simplest form.
then the answer is below ↓
Step-by-step explanation:
9:4
of his first 40 games: 3/5 *40=3*8=24 wins
=> of his first 40 games: 24 wins and 40-24=16 losses
next 12 games: 12 wins
so, for all 52 games: 24+12=36 wins and 16 losses
36 wins and 16 losses
wins: losses=> 36:16=> 9:4
