I need it solved and explaned
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The range of this function is y is equal to all real numbers such that y 0.
In order to find the range of y, we must look for the minimum or maximum value. In a quadratic, this number exists at the vertex. To find the vertex, we use the equation -b/2a, where a is equal to the coefficient of x^2 and b is equal to the coefficient of x. Since there is no x, the coefficient is 0.
x value of vertex = -b/2a
x value of vertex = -0/2(1)
x value of vertex = 0
So then we can look for the minimum y value by plugging in the x value into the equation.
y = x^2
y = x^2
y = 0
Therefore the minimum is 0 and there is no maximum.