For this case we must solve the following questions:
Question 1:
We should simplify the following expression:

Applying double C we have:

By definition of multiplication of powers of the same base we have to place the same base and add the exponents:
Canceling common terms:

Answer:
Option A
Question 2:
We should simplify the following expression:

So, we have:

Simplifying common terms:

Answer:
Option D
Question 3:
We factor the following expressions to rewrite the experience:
<em>
: </em>We look for two numbers that multiplied give 10 and added 7:

<em>
</em> We look for two numbers that multiplied give -50 and added -5:

<em>
</em>
Rewriting the given expression we have:

We simplify common terms in the numerator and denominator we have:

Answer:
Option D
Answer:
it would take 2.25 1/3 cups if you are looking for an exact answer, or if you are looking for the minimum amount of 1/3 cups necessary to make 3/4 it would be 3.
Step-by-step explanation:
You can solve this by cross multiplying 1/3 and 3/4
You will get 9/4 which simplifies to 2 1/4 or 2.25
Step-by-step explanation:
When a number is grouped with the x in this problem it will move the graph right (if it is is minus) and it will
move it left ( if it is plus), therefore the original graph will be move to the left 5 units.
Answer:
y = -12
Step-by-step explanation:
You first calculate the x coordinate using the equation x =
, which in this case is
.
Then plug that x value into the equation to get the y coordinate:
4(-1)²+8(-1)-8 = -12
We have $8.50 an hour gross minus $2.15 an hour tax and bennys. Then $3.75 daily expense. In one week our net take-away y after x hours is
y = x(8.50 - 2.15) - 5(3.75)
That's the answer, or we can simplify it to
Answer: y = 6.35 x - 18.75
Answer: The slope, 6.35, is the net dollars per hour <em>before weekly expenses.</em>
Answer: The y intercept, -18.75, is the weekly expense, negative because it's an expense.
To make $120 in a week, we solve for x where y=120
120 = 6.35x - 18.75
138.75 = 6.35 x
x = 138.75 / 6.35 = 21.8503937007874
That wasn't the nice round number I was expecting/hoping for. I don't see a mistake so let's go with
Answer: 21.85 hours to make $120