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just olya [345]
3 years ago
10

1. What is the difference between a synthetic resource and a Natural Resource? This is technology.and I need help pls help!!!!!!

!!!!!!!
Chemistry
1 answer:
Elodia [21]3 years ago
4 0

Answer:

Natural materials are those that are found in nature and have not been made by humans. By comparison, synthetic materials are man-made and cannot be found in nature. Synthetic products are usually created in laboratories by mixing different chemicals, or prepared compounds and substances made in a laboratory.

Explanation:

Natural materials are those that are found in nature and have not been made by humans. By comparison, synthetic materials are man-made and cannot be found in nature. Synthetic products are usually created in laboratories by mixing different chemicals, or prepared compounds and substances made in a laboratory

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How many Mg 2+ ions are present in 3.00 moles of MgCl2
Nostrana [21]
This is what I got hope this makes sense:There is 1 mol of Mg 2+ ions in one mole of MgCl2, we can get that from the formula.
Multiply 3.00 moles by 6.022x10^23 to get moles of MgCl2.
There are 6.022x10^23 ions in one mole of substance.
(3.00)(6.022x10^23)
=1.81x10^24 Mg 2+ ions
Hope it helps though
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Water has a density of 1.0 g/mL. Which of these objects will float in water
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3 years ago
Why do the Noble gases have the highest ionization energies across a period?
Kitty [74]

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3 years ago
A compound consists of 75% magnesium and 25% oxygen. Find the empirical formula.
laila [671]
<h2>Answer:</h2>

% Composition of elements:

  • Magnesium = 75%
  • Oxygen = 25%

Atomic mass of given elements:

  • Magnesium = 24 g
  • Oxygen = 16 g

Now, divide % composition by Atomic mass:

\footnotesize\implies Mg = \dfrac{\% \:  Composition}{Atomic  \: mass} =  \dfrac{75}{24}  =  \bf 3.125

\footnotesize\implies O = \dfrac{\% \:  Composition}{Atomic  \: mass} =  \dfrac{25}{16}  =  \bf 1.5625

Simplest Ratio:

\footnotesize\implies Mg  =  \dfrac{3.125}{1.5625}  = 2

\footnotesize\implies O  =  \dfrac{1.5625}{1.5625} = 1

Empirical Formula:

\footnotesize\implies \underline{ \boxed{ \red{ \bf Empirical \:  Formula = Mg_2O}}}

8 0
3 years ago
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