MnO2 + 4HCl = MnCl2 + Cl2 + 2H2O
m(HCl) = 36.45/48.2 = 0.76
every 4 moles of HCl will only react with 1 mole MnO2 and there is less HCl therefore HCl will be used up first.
Excess MnO2 = 0.86 - (0.76/4) = 0.67m
grams MnO2 = 0.67x 86.93= 58.24grams left over.
Every 4 moles HCl will only form 1 mole Cl2 so m(Cl2)=0.76/4=0.19
0.19x70.9=13.47grams Chlorine formed
The ballon would have deflated in order to decrease the volume
Energy, I think, haven't done that since 8th grade
Answer:
B. 1 triple bond and 2 single bonds
Explanation:
C2Cl2 has linear structure.
For its Lewis structure, the C2Cl2 molecule has a total of 22 valence electrons. Each Carbon (C) atom has 4 valence electrons and 7 atoms in each chlorine atoms.
So, after pairing in C2Cl2, Chlorine (Cl) form 2 single bonds, one with each carbon atom andboth the Carbon (C) atoms form one triple bond with each other.