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natita [175]
3 years ago
14

A cube is 4 cm on each side. What is its volume? Answer: 64cm^3

Chemistry
1 answer:
Anit [1.1K]3 years ago
5 0

Answer:

yeah

Explanation:

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It 1:1 I had an online review and thats the answer it told me it was.
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3 years ago
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3- a) write the formula unit of calcium fluoride.
zvonat [6]

Answer:

a) CaF₂.

b) 7.81g of CaF₂ are present.

Explanation:

a) The calcium ion has as charge Ca²⁺ and fluoride ion is F⁻, that means formula unit is:

CaF₂

b) 1 molecule of CaF₂ contains 2 anions, F⁻. Thus, the moles of CaF₂ is:

1.2x10²³ anions * (1 moleculeCaF₂ / 2 anions) = 6x10²² molecules of CaF₂

6.022x10²³ molecules = 1mol:

6x10²² molecules of CaF₂ * (1mol / 6.022x10²³molecules) = 0.10 moles CaF₂.

1 mole of CaF₂ has a mass of 78.07g:

0.10 moles CaF₂ * (78.07g / mol) =

7.81g of CaF₂ are present

5 0
3 years ago
PLeaseee ITS Timedddd + BrainlIESTT
uysha [10]

Answer:

d. 12.3 grams of Al2O3

Explanation:

The balanced chemical equation of this chemical reaction is as follows:

4Al + 3O2 --> 2Al2O3

Based on the balanced equation, 4 moles of aluminum (limiting reagent) reacts to form 2 moles of aluminum oxide (Al2O3).

First, we need to convert the mass of aluminum to moles using the formula;

mole = mass/molar mass

Molar mass of Al = 27g/mol

mole = 6.50/27

= 0.241mol of Al.

Hence, if 4 moles of aluminum (limiting reagent) reacts to form 2 moles of aluminum oxide (Al2O3).

Then, 0.241mol of Al will produce (0.241 × 2/4) = 0.241/2 = 0.121mol of Al2O3.

Convert this mole value to molar mass using mole = mass/molar mass

Molar mass of Al2O3 = 27(2) + 16(3)

= 54 + 48

= 102g/mol

mass = molar mass × mole

mass = 102 × 0.121

mass of Al2O3 = 12.34grams.

5 0
3 years ago
Select the correct answer.
White raven [17]

Answer:

The average atomic mass of sulfur is 32.065u

6 0
4 years ago
If I initially have 4.0 L of a gas at a pressure of 1.1 atm and a temperature of 298 K, what will the volume be if I increase th
DochEvi [55]

Answer:

1.34L

Explanation:

1 torr = 0.00132atm

P2= 2584torr = 3.41atm

T2= 37°C = 273+37 = 310K

Using combined gas law

P1V1/T1 = P2V2/T2

(1.1×4.0)/298 = (3.41 × V2)/310

V2= (1.1×4×310)/(298×3.41)

V2= 1.34L

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3 years ago
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