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kap26 [50]
2 years ago
9

Which of the following equations could be used to solve for x in the triangle shown?

Mathematics
2 answers:
iVinArrow [24]2 years ago
7 0

Answer:

a

Step-by-step explanation:

because do sin 48 x X to find it

horsena [70]2 years ago
4 0
Yeah I think it number A
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9. The maximum horizontal range of a projectile is given by the formula R= u2/g where u is the initial velocity and g is the acc
Helen [10]
<h2>Hello!</h2>

The answer is:

The velocity with which the ball can be thrown to have a maximum range of 20 meters is equal to 14 m/s.

u=14\frac{m}{s}

<h2>Why?</h2>

To solve the problem and find the velocity, we need to isolate it from the equation used to calculate the maximum horizontal range.

We have the equation:

R=\frac{u^{2} }{g}

Where,

R is the maximum horizontal range.

u is the initial velocity.

g is the gravity acceleration.

Also, from the statement we know that:

R=20m\\g=9.8\frac{m}{s^{2} }

So, using the given information, and isolating, we have:

R=\frac{u^{2} }{g}

R*g=u^{2}

u^{2}=R*g=20m*9.8\frac{m}{s^{2} }=196\frac{m^{2} }{s^{2} }\\\\u=\sqrt{196\frac{m^{2} }{s^{2}}}=14\frac{m}{s}

Hence, we have that the velocity with which the ball can be thrown to have a maximum range of 20 meters is equal to 14 m/s.

u=14\frac{m}{s}

Have a nice day!

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