Write the equation of the line through (5, -4) m=1

Which of the following ordered pairs make this equation true? Y = 2x - 7 A. (1,9) B. (-3, 4) C. (4,1) D. (-1, 5)

gregori [183]

Answer:

(4,1)

Step-by-step explanation:

Using substitution you can determine that 2*4-7 is in fact equal to 1

3 0

2 years ago

Y=2x-5 3x+8y+32=56 What does y and x equal?

AVprozaik [17]

Y = 2x - 5
3x + 8y + 32 = 56
3x + 8(2x - 5) + 32 = 56
3x + 8(2x) - 8(5) + 32 = 56
3x + 16x - 40 + 32 = 56
19x - 8 = 56
 + 8 + 8
 19x = 64
 19 19
 x = 3.4
y = 2(3.4) - 5
y = 6.8 - 5
y = 1.8
(x, y) = (3.4, 1.8)

5 0

2 years ago

Two students walk in the same direction along a straight path, at a constant speed - one at .90 m/s and the other at 1.90 m/s.a.

anyanavicka [17]

Answer:

a)The second student arrive 7 minutes and 36 seconds sooner

b)They have to walk 598,51 m

Step-by-step explanation:

Speed= Distance/Time

We are looking for time now

Time = Distance/Speed

First student

Time = 780 m/0.90 m/s=866,66 seconds

Second student

Time = 780 m/1.90 m/s=410,52 seconds

Difference=866,66-410,52= 456,14 seconds

In minutes

Difference= 456,14 seconds /60=7 minutes 36 seconds

Distance=Speed x Time

Speed¹ x Time¹ =Speed² x Time²

Time¹= Time² + 5.50 min

5.50 min =350 seconds

Time² =Speed¹ x Time¹ /Speed²

Time² =Speed¹ x (Time² + 350 seconds ) /Speed²

Time² =0.9 x (Time² + 350 seconds ) /1.9

Time² =0,4737 x (Time² + 350 seconds )

Time² =0,4737 Time² + 165,79 seconds

Time² - 0,4737 Time² = 165,79 seconds

0,5263 Time² = 165,79 seconds

Time² = 165,79 seconds/0,5263 =315,01 seconds

Distance=1,9 x 315,01 seconds = 598,51 m

5 0

2 years ago

Help me please thank you.

OLga [1]

Top row - Left Row :

Order : Left to Right

{11.7 - below(negative)} , {11.6 - below(negative)} , {12 - exactly filled} , {12.2 - above(positive)}

Middle Row :

Order : Left to Right

{11.1 - below(negative)} , {11.2 - below(negative)} , {11.9 - below(negative)} , {12.5 - above(positive)}

Right Row :

Order : Left to Right

{12 - exactly filled} , {11.4 - below(negative)} , {11.5 - below(negative)} , {10.8 - below(negative)}

8 0

2 years ago

A production process is checked periodically by a quality control inspector. the inspector selects simple random samples of 30 f

777dan777 [17]

Answer:

Population Mean = 2.0

Population Standard deviation = 0.03

Step-by-step explanation:

We are given that the inspector selects simple random samples of 30 finished products and computes the sample mean product weight.

Also, test results over a long period of time show that 5% of the values are over 2.1 pounds and 5% are under 1.9 pounds.

Now, mean of the population is given the average of two extreme boundaries because mean lies exactly in the middle of the distribution.

So, Mean, $\mu$ = $\frac{1.9+2.1}{2}$ = 2.0

Therefore, mean for the population of products produced with this process is 2.

Since, we are given that 5% of the values are under 1.9 pounds so we will calculate the z score value corresponding to a probability of 5% i.e.

z = -1.6449 {from z % table}

We know that z formula is given by ;

$Z = \frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

-1.6449 = $\frac{1.9 - 2.0}{\frac{\sigma}{\sqrt{n} } }$ ⇒ $\frac{\sigma}{\sqrt{n} } = \frac{-0.1}{-1.6449}$

⇒ $\sigma =$ 0.0608 * $\sqrt{30}$ {as sample size is given 30}

⇒ $\sigma$ = 0.03 .

Therefore, Standard deviation for the population of products produced with this process is 0.0333.

7 0

3 years ago