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3 years ago

YALL HELP PLEASE THANK U

Mathematics

2 answers:

Alenkinab [10]3 years ago

8 0

Step-by-step explanation:

Given Vertex (5,4) and focus (8,4)

It can be easily noticed that focus and vertex lie on the same horizontal line y = 4

Obviously, the axis of symmetry is a horizontal line ( a line perpendicular to y-axis). Also, the focus lies to the right of the vertex so the parabola will open up rightward.

(y−k)^2=4a(x−h)

a=8-5=3 as y coordinates are the same.

Since the focus lies to the left of vertex, a = 3

(y−4)^2=4⋅3⋅(x−5)

(y−4)^2=12(x−5)

is the equation of the parabola.

Ede4ka [16]3 years ago

4 0

Answer:

I am not getting this question

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In the diagram below AFB is congruent to EFD if EFD = 5x + 6, DFC = 19x - 15, and EFC = 17x + 19, find AFE

yanalaym [24]

The angle m∠AFE is 128 degrees.

<h3>How to find angles?</h3>

∠AFB ≅ ∠EFD

∠EFD = 5x + 6

m∠DFC = (19x - 15)°

m∠EFC = (17x + 19)°

m∠AFE = ?

m∠AFB + m ∠EFD + m∠AFE = 180

Therefore,

5x + 6 + 5x + 6 + m∠AFE = 180

5x + 5x + 6 + 6 + m∠AFE = 180

10x + 12 + m∠AFE = 180

10x + m∠AFE = 180 - 12

10x + m∠AFE = 168

m∠AFE = 168 - 10x

m∠EFC = m ∠EFD + m∠DFC

17x + 19 = 5x + 6 + 19x - 15

17x - 5x - 19x = 6 - 15 - 19

-7x = - 28

x = 28 / 7

x = 4

Therefore,

m∠AFE = 168 - 10x

m∠AFE = 168 - 10(4)

m∠AFE = 168 - 40

m∠AFE = 128°

Therefore, the angle m∠AFE = 128°

learn more on angles here: brainly.com/question/13212279

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7 0

2 years ago

Reduce to lowest terms. 3m^2-3n^2/6m-6n A) -m-n/2 B) m-n/2 C) m+n/2

USPshnik [31]

Answer:

C. m+n/2

Step-by-step explanation:

Factor out the 3 in the numerator and apply the difference of squares, factor out the 6 in the denominator, and reduce where applicable. It'll all cone out to look like option C.