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disa [49]
2 years ago
11

Consider the equality xy=k. Write the following inverse proportion: y is inversely proportional to x. When y = 2, x = 14.

Mathematics
1 answer:
Alika [10]2 years ago
7 0

\huge\text{Hey there!}

\huge\textbf{Equation \#1.}

\mathbf{\dfrac{2}{1} = \dfrac{k}{14}}

\huge\textbf{Cross multiply the given numbers}\\\huge\textbf{you have listed.}

\mathbf{2\times14 = k \times1}

\mathbf{2\times14 = 1\times k}

\mathbf{28 = 1k}

\mathbf{1k = 28}

\huge\textbf{DIVIDE 1 to BOTH SIDES}

\mathbf{\dfrac{28}{1} = \dfrac{1k}{1}}

\huge\textbf{SIMPLIFY IT!}

\mathbf{k = \dfrac{28}{1}}

\mathbf{k = 28}

\huge\text{Therefore, your answer is: \boxed{\mathsf{k = 28}}}\huge\checkmark

\huge\textbf{Equation \#2.}

\mathbf{\dfrac{1}{k} = \dfrac{14}{2}}

\huge\textbf{Cross multiply the given numbers}\\\huge\textbf{you have listed.}

\mathbf{1\times 2 = 14\times k}

\mathbf{2 = 14k}

\mathbf{14k = 2}

\huge\textbf{DIVIDE 14 to BOTH SIDES}

\mathbf{\dfrac{14k}{14} = \dfrac{2}{14}}

\huge\textbf{SIMPLIFY IT!}

\mathbf{k = \dfrac{2}{14}}

\mathbf{k = \dfrac{2\div2}{14\div2}}

\mathbf{k = \dfrac{1}{7}}

\huge\text{Therefore, your answer is: \boxed{\mathsf{k = \dfrac{1}{7}}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

<h3>~\frak{Amphitritr1040:)}</h3>
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<h3>4 units</h3>

Hope this helps you

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