The vertex of this parabola is at (3,5). When the Y value is 6X value is negative one what is the coefficient of the squared ter
1 answer:
We know that equation of a parabola is given by :-
y = a(x-h)² + k
Where (h,k) is the vertex of parabola and (x,y) is any point on its curve.
Given that vertex of parabola is (3,5) and one point (x,y) is (6,-1).
We can plug the given information in the equation of parabola and solve it for value of 'a' :-
-1 = a(6 - 3)² + 5
-1 = a(3)² + 5
-1 = 9a + 5
9a = -1 -5 = -6
a =
a = is the final answer.
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Solving the equations by graphing requires plotting the given functions.
y=x^2-3
x-y=1
thus the plot will be as shown in the picture. The solutions are:
(-2,-1) and (2,1)
y=x^2-3
x-y=1
thus the plot will be as shown in the picture. The solutions are:
(-2,-1) and (2,1)
Answer:
<u>Step-by-step explanation:</u>
y = A cos (Bx - C) + D
- A (amplitude) = max - D
- B = Period/2π ---> Period is the distance from max to next max
- C = B · Phase Shift ---> Phase shift is distance from y-axis to max
- D (vertical shift) = (max + min)/2
D = (max + min)/2 = (3 - 11)/3 = -4
A = max - D = 3 - (-4) = 7
Period = 9π/4 - π/4 = 8π/4 = 2π
B = Period/2π = 2π/2π = 1
Phase Shift = π/4 - 0 = π/4
C = B · Phase Shift = 1 · π/4 = π/4
Equation:
y = 7 cos (1·x - π/4) + (-4)