Answer:
The bones were 12,485 years old at the time they were discovered.
Step-by-step explanation:
Amount of the element:
The amount of the element after t years is given by the following equation, considering the decay rate proportional to the amount present:

In which A(0) is the initial amount and k is the decay rate, as a decimal.
The radioactive element carbon-14 has a half-life of 5750 years.
This means that
, and we use this to find k. So







So

A scientist determined that the bones from a mastodon had lost 77.8 % of their carbon-14. How old were the bones at the time they were discovered?
Had 100 - 77.8 = 22.2% remaining, so this is t for which:

Then






The bones were 12,485 years old at the time they were discovered.
Answer:
Step-by-step explanation:
For similar figures, side lengths (and any other linear measure) are proportional. Areas are proportional to the square of the scale factor for side lengths.
Perimeter 1/Perimeter 2 = CD/EF
21/18 = CD/6
CD = 6(21/18)
CD = 7 . . . cm
__
Area 2/Area 1 = (Perimeter 2/Perimeter 1)²
Area 2/98 = (18/21)²
Area 2 = 98(6/7)²
Area 2 = 72 . . . cm²
64 pages
divide 40 by 5 for pages printed in 1 minute then multiply this by 8
× 8 = 8 × 8 = 64 pages
Answer:
A.
Step-by-step explanation:
y=loga(x) is just the same as x=a^y
Answer:
20
Step-by-step explanation:
there are 10 2s
2×10 =20