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Fynjy0 [20]
3 years ago
6

Which statement is true about figures ABCD and A'B'C'D?

Mathematics
1 answer:
Anika [276]3 years ago
5 0

Answer:

Step-by-step explanation:

To understand the transformation better we will take a point B first.

Coordinates of B → (3, 0)

When we rotate this point by 180° counterclockwise about the origin, rule to be followed,

(x, y) → (-x, -y)

By this rule, coordinates of B'' will be,

B(3, 0) → B''(-3, 0)

Now we translate the point B by 2 units right.

Rule for the translation is,

(x, y) → [(x + 2), 0]

Following this rule,

B''(-3, 0) → B'[(-3+2), 0]

             → B'(-1, 0)

We can conclude with the statement, "Figure ABCD was rotated by 180° about the origin followed by the translation of 2 units to the right" to get the new figure A'B'C'D' similar to pre-image ABCD.

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Tommy and Mark earned a total of $88.00 raking leaves for Mrs. Bopp. Tommy raked for 5 hours and Mark raked for 3 hours. If the
kompoz [17]

Answer:

<em>Tommy earned $55</em>

Step-by-step explanation:

<u>Proportions</u>

Tommy and Mark made $88 raking leaves for Mrs. Bopp. They were paid the same rate and Tommy raked for 5 hours while Mark raked for 3 hours.

The total time both raked is 5+3=8 hours. The rate Mrs. Bopp paid them was $88/8 = $11 per hour.

Tommy raked 5 hours, so he earned 5*$11 = $55

Tommy earned $55

8 0
3 years ago
How to solve 5(2b-3)-1(11b+1)=20
son4ous [18]

Answer:

b = -36

Step-by-step explanation:

Start by distributing both th 5 and the negative 1 into their corresponding parentheses.

((5*2b)-(5*3)) > (10b - 15)

((-1*11b)+(-1*1)) > (-11b - 1)

so you have:

10b - 15 - 11b - 1 = 20

Next you would Combine like terms to get:

-b - 16 = 20

Add the 16 to both sides

-b = 36

and divide each side by -1

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3 0
3 years ago
Suppose the probability of an athlete taking a certain illegal steroid is 10%. A test has been developed to detect this type of
Travka [436]

Answer:

93.25% probability that they have taken this steroid

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Positive test

Event B: Taking the steroid.

Suppose the probability of an athlete taking a certain illegal steroid is 10%.

This means that P(B) = 0.1

Given that the athlete has taken this steroid, the probability of a positive test result is 0.995.

This means that P(A|B) = 0.995

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99.5% of 10%(If the athlete has taken).

100-99.2 = 0.8% of 100-10 = 90%(Athlete has not taken)

Then

P(B) = 0.995*0.1 + 0.008*0.9 = 0.1067

Given that a positive test result has been observed for an athlete, what is the probability that they have taken this steroid

P(B|A) = \frac{P(B)*P(A|B)}{P(A)} = \frac{0.1*0.995}{0.1067} = 0.9325

93.25% probability that they have taken this steroid

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True or false euclidean geometry is geometry on a sphere
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