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DiKsa [7]
3 years ago
6

What is the radius of a circle that has a circumference of 81 π square inches?

Mathematics
2 answers:
dolphi86 [110]3 years ago
8 0
2 the reason why is because I need 5 points. Hope that helps!
ira [324]3 years ago
6 0

Answer:

r≈12.89

Step-by-step explanation:

Using the formula

C=2πr

Solving for r

r=C

2π=81

2·π≈12.89155

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The Quotient 250 divided by 5/8 tells about how far a sloth may move in one hour How far can a sloth go in 90 minutes?
Hunter-Best [27]

Given condition is:

A sloth moves in one hour = \frac{250}{5/8}

\frac{5}{8}=0.625

So, a sloth moves in one hour = \frac{250}{0.625}=400 units

Hence, in 60 minutes a sloth moves = 400

In 1 minute sloth will move = \frac{400}{60}

In 90 minutes it will  move = \frac{400}{60}\times90=600

The answer is 600 units.

4 0
4 years ago
Read 2 more answers
What’s equivalent (2x^5)^3
Over [174]

Answer:

8x^15

Step-by-step explanation:

(2x5)3

=(2x5)3

=2x5*2x5*2x5

=8x15

6 0
3 years ago
21 + (-21) + (-4) please help me out with this question
max2010maxim [7]

Answer:

-4

Step-by-step explanation:

Adding 21 and -21 cancel each other out so you're left with -4

4 0
4 years ago
Help ASAP BRAIN IF RIGHT The width of a rectangle is 12 units. Can the perimeter P of the rectangle be 60 units when its length
bonufazy [111]

Answer:

Yes, because P = 2x +2(12)

Step-by-step explanation:

As the formula for perimeter is 2(L+B).

Let L=x=18

B=12

Then, perimeter, P=2(18+12) = 2(30) = 60

Hence, we get the perimeter as 60 units.

6 0
3 years ago
A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 5 ftys along
Sever21 [200]

25/3 ft/s is speed of the tip of his shadow moving when a man is 40 ft from the pole given that a street light is mounted at the top of a 15-ft-tall pole and the man is 6 ft tall who is walking away from the pole with a speed of 5 ft/s along a straight path. This can be obtained by considering this as a right angled triangle.

<h3>How fast is the tip of his shadow moving?</h3>

Let x be the length between man and the pole, y be the distance between the tip of the shadow and the pole.

Then y - x will be the length between the man and the tip of the shadow.

Since two triangles are similar, we can write

\frac{y-x}{y} =\frac{6}{15}

⇒15(y-x) = 6y

15 y - 15 x = 6y

9y = 15x

y = 15/9 x

y = 5/3 x

Differentiate both sides

dy/dt = 5/3 dx/dt

dy/dt is the speed of the tip of the shadow, dx/dt is the speed of the man.

Given that dx/dt = 5 ft/s

Thus dy/dt = (5/3)×5 ft/s

dy/dt = 25/3 ft/s

Hence 25/3 ft/s is speed of the tip of his shadow moving when a man is 40 ft from the pole given that a street light is mounted at the top of a 15-ft-tall pole and the man is 6 ft tall who is walking away from the pole with a speed of 5 ft/s along a straight path.

Learn more about similar triangles here:

brainly.com/question/8691470

#SPJ4

3 0
2 years ago
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