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2 years ago

5

2 A cafe sells cakes and scones.

1 answer:

Alecsey [184]2 years ago

8 0

30 cakes on tuesday

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Write an equation of the line that passes through the points (-2,-7) and (0,-4).

yaroslaw [1]

Answer:

Step-by-step explanation:

( $x_{1}$ , $y_{1}$ )

( $x_{2}$ , $y_{2}$ )

m = $\frac{y_{2} -y_{1} }{x_{2} -x_{1} }$

y - $y_{1}$ = m( x - $x_{1}$ ) point - slope form of a line.

y = mx + b slope- intercept form of a line.

~~~~~~~~~~~~~~~~~

( - 2, - 7 )

( 0, - 4 )

m = $\frac{- 4 - (-7)}{0 - (- 2)}$ = $\frac{3}{2}$

y - ( - 4 ) = $\frac{3}{2}$ ( x - 0 )

y + 4 = $\frac{3}{2}$ x

<em>y = </em> $\frac{3}{2}$ <em> x - 4</em> slope- intercept form

<em>3x - 2y = 8</em> standard form

5 0

2 years ago

The map below shows the location of 3 houses where you had to do lawn work today. Your truck gets 8 miles per gallon of gasoline

Brums [2.3K]

<u>Answer:</u>

$3.80

<u>Step-by-step explanation:</u>

We are given a graph showing the location of 3 houses where you had to do lawn work today, with the distances from your house.

Given that one truck gets 8 miles per gallon of gasoline and gas costs $1.52 per gallon, we are to find the total cost of the gas used.

Total distance = 7 + 3 + 4 + 6 = 20 miles

Gallons of gas used = 20 / 8 = 2.5

Total cost of gas used = 2.5 * 1.52 = $3.80

6 0

2 years ago

Find the area of the parallelogram.

ArbitrLikvidat [17]

Answer:

$160 {ft}^{2}$

Step-by-step explanation:

Area of parallelogram =base x height

Area=20 x 8=160

Units=

$ft {}^{2}$

6 0

3 years ago

Read 2 more answers

What is the argument of the complex number shown? z=sqrt(2)/2 - sqrt(2)/2(i)

saveliy_v [14]

Answer:7pi\4

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

For the following telescoping series, find a formula for the nth term of the sequence of partial sums

gtnhenbr [62]

I'm guessing the sum is supposed to be

$\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}$

Split the summand into partial fractions:

$\dfrac1{(5k-1)(5k+4)}=\dfrac a{5k-1}+\dfrac b{5k+4}$

$1=a(5k+4)+b(5k-1)$

If $k=-\frac45$ , then

$1=b(-4-1)\implies b=-\frac15$

If $k=\frac15$ , then

$1=a(1+4)\implies a=\frac15$

This means

$\dfrac{10}{(5k-1)(5k+4)}=\dfrac2{5k-1}-\dfrac2{5k+4}$

Consider the $n$ th partial sum of the series:

$S_n=2\left(\dfrac14-\dfrac19\right)+2\left(\dfrac19-\dfrac1{14}\right)+2\left(\dfrac1{14}-\dfrac1{19}\right)+\cdots+2\left(\dfrac1{5n-1}-\dfrac1{5n+4}\right)$

The sum telescopes so that

$S_n=\dfrac2{14}-\dfrac2{5n+4}$

and as $n\to\infty$ , the second term vanishes and leaves us with

$\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}=\lim_{n\to\infty}S_n=\frac17$

7 0

3 years ago