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3 years ago

Someone help me on this one

Mathematics

2 answers:

Murljashka [212]3 years ago

6 0

I’m pretty sure it would be 1/5, because scaling is changing the y values of the function. If the y value of the original is 10, you need to multiply/scale the new one by 1/5 to get the y value of 2

iogann1982 [59]3 years ago

3 0

Answer: Times 5

Step-by-step explanation:

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A sporting goods store manager was selling a ski set for a certain price. The manager offered the markdowns shown, making the

Leno4ka [110]

Answer:
The original selling price is $520.632
Explanation:
Consider the initial selling price be $x
After marking down 10%,
Final Selling price = Selling price(1-10%)
Selling price = x – 10% of x = x – 0.1x = 0.9x
After marking 30%
Final Selling price = Selling price(1-10%)
Selling price = 0.9x – 0.3*0.9x = 0.9x – 0.27x = 0.63x
According to the question,
0.63x = 328

Therefore, the original selling price is $520.632

5 0

3 years ago

Read 2 more answers

If a line with a slope of -2 crosses the y-axis at (0, 3), what is the equation of the line?

MA_775_DIABLO [31]

The slope-intercept form: y = mx + b

m - the slope
b - the y-intercept

m = -2; (0; 3) → b = 3

subtitute

y = -2x + 3

4 0

4 years ago

Read 2 more answers

!!!!!!PLZ HELP ME!!!!!!

Vinvika [58]

Answer:

$-2\frac{4}{7}$

Step-by-step explanation:

$-3\frac{2}{7} -(-\frac{5}{7})$

$-\frac{23}{7} -(-\frac{5}{7})$

$-\frac{23}{7} + \frac{5}{7}$

$-\frac{18}{7} = -2\frac{4}{7}$

7 0

3 years ago

Mason opens a savings account by making a $165.85 deposit. Every week, he deposits another $20.50 in the account.

Maslowich

C! Hope this helps :D

4 0

3 years ago

Read 2 more answers

Solve the system of equations.

emmainna [20.7K]

$x = \frac{ 419 }{ 113 } ~,~y = -\frac{ 208 }{ 113 } ~,~z = \frac{ 21 }{ 113 }$

<h2>Explanation:</h2>

We have the following system of three linear equations:

$\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\5~ x&+~~8~ y&+~~~~ z&~=~4\\4~ x&+~~5~ y&+~~2~ z&~=~6\end{array}$

Let's use elimination method in order to get the solution of this system of equation, so let's solve this step by step.

Step 1: Multiply first equation by $-5/2$ and add the result to the second equation. So we get:

$\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\&-~~~2~ y&-~~~79~ z&~=~-11\\4~ x&+~~5~ y&+~~2~ z&~=~6\end{array}$

Step 2: Multiply first equation by −2 and add the result to the third equation. So we get:

$\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\&-~~~2~ y&-~~~79~ z&~=~-11\\&-~~~3~ y&-~~~62~ z&~=~-6\end{array}$

Step 3: Multiply second equation by −32 and add the result to the third equation. So we get:

$\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\&-~~~2~ y&-~~~79~ z&~=~-11\\&&+~~\frac{ 113 }{ 2 }~ z&~=~\frac{ 21 }{ 2 }\end{array}$

Step 4: solve for z.

$\begin{aligned} \frac{ 113 }{ 2 } ~ z & = \frac{ 21 }{ 2 } \\ z & = \frac{ 21 }{ 113 } \end{aligned}$

Step 5: solve for y.

$\begin{aligned}-2y-79z &= -11\\-2y-79\cdot \frac{ 21 }{ 113 } &= -11\\y &= -\frac{ 208 }{ 113 } \end{aligned}$

Step 6: solve for x by substituting $y=-\frac{208}{113}$ and $z = \frac{21}{113}$ into the first equation:

$2x+4(-\frac{208}{113})+32(\frac{21}{113})=6 \\ \\ 2x-\frac{832}{113}+\frac{672}{113}=6 \\ \\ 2x=6+\frac{832}{113}-\frac{672}{113} \\ \\ 2x=\frac{838}{113} \\ \\ x=\frac{319}{113}$

Finally:

$x = \frac{ 419 }{ 113 } ~,~y = -\frac{ 208 }{ 113 } ~,~z = \frac{ 21 }{ 113 }$

<h2>Learn more:</h2>

Solving System of Equations: brainly.com/question/13121177

#LearnWithBrainly

7 0

4 years ago