Answer:
51,111%
Step-by-step explanation:
We know that 45% have a dog but no cat. While 23% have both a dog and a cat.
Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)
= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%
The probability that a student’s family owns a cat if the family owns a dog is 51,111%
Answer:
Step-by-step explanation:
Answer:
1 or 4/4
It is certain that the spinner will land on a number less that 5 because the selections are labeled 1 to 4 and the numbers 1 to 4 are less than 5.
(0.4n)(16n) = (0.4)(16)(n)(n) = 6.4n²
Answer: 6.4n²
