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3 years ago

Hi, I hope your having a good day so far..

Mathematics

2 answers:

maria [59]3 years ago

4 0

Answer:

I am having a great day

3 1/5, 3.22, 3.4, 3.58, 3.64

Step-by-step explanation:

Me Brainliest please

8_murik_8 [283]3 years ago

3 0

3.4
3 1/5= 3.2
35.8%= 0.358
3.64
322%= 3.22
So,
35.8%, 3 1/5, 322%, 3.4, 3.64

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Solve for x: 1 < x + 3 < 4

MrRa [10]

It’s clearly number 2. 3 and 4 don’t have a 4 so it leaves 1 and 2 1 has gt so that’s wrong so it’s 2 because it has lt

4 0

3 years ago

Find an equation of the line described below. Write the equation is slope-intercept from ( solved for y), when possible. Through

Sladkaya [172]

Answer:

The equation of the line that is passing through the point (5,4) and is parallel to x-axis would be $y=4$

Step-by-step explanation:

Given that the line passes through the point (5,4).

As the line is parallel to the x-axis, the slope of the line would be zero.

And we have point (5,4) from which the line is passing.

So, $x_1=5\ ,\ y_1=4\ and\ m=0$

The equation of the line passing through point $(x_1,y_1)$ is

$y-y_1=m(x-x_1)\\y-4=0(x-5)\\y-4=0\\y=4$

So, the equation of the line that is passing through the point (5,4) and is parallel to x-axis would be $y=4$

4 0

4 years ago

I need help plz ASAP

netineya [11]

Answer: x=8

Step-by-step explanation:

the sum of the interior angles of a quadrilateral is 360 (number of sides-2 * 180)

$14x-7+11x-2+93+76= 360\\25x + 160=360\\25x= 200\\x=8$

4 0

3 years ago

Read 2 more answers

2) Line segment MK has endpoints at (2, 3) and (5, ?4). Segment M'K' is the reflection of MK over the y-axis. Which statement de

Marianna [84]

Answer:

Option C -M'K' is the same length as MK

Step-by-step explanation:

Given : Line segment MK has endpoints at (2, 3) and (5,4)

M'K' is the reflection of MK over the y-axis

By definition of reflection: reflection of point (x,y) across the the y-axis is the point (-x,y)

which implies M'K' has end points (-2,3) and (-5,4)

Now, we find the length of MK

let $(x_1,y_1)=(2,3)\\\\(x_2,y_2)=(5,4)$

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

⇒ $d=\sqrt{(2-5)^2+(4-3)^2}$

⇒ $d=\sqrt{9+1}$

⇒ $d=\sqrt{10}$ ....(1)

Now, we find the length of M'K'

let $(x_1^{'},y_1^{'})=(-2,3)\\\\(x_2^{'},y_2^{'})=(-5,4)$

$d^{'}=\sqrt{(x_2^{'}-x_1^{'})^2+(y_2^{'}-y_1^{'})^2}$

⇒ $d^{'}=\sqrt{(-2+5)^2+(3-4)^2}$

⇒ $d^{'}=\sqrt{9+1}$

⇒ $d^{'}=\sqrt{10}$ .....(2)

from (1) and (2) we simply show that the length of MK and M'K' is equal

we can also refer the figure attached for reflection of MK and M'K'

therefore, Option C is correct

3 0

4 years ago

Read 2 more answers

Graph f(x)=−3/4x−4 . Use the line tool and select two points to graph the line.

lions [1.4K]

Answer:

Two points on the line would be (0, -4) and (4, -7)

Step-by-step explanation:

In order to find this, we can start at the y-intercept. The y-intercept is the constant at the end of the equation. In this case it is -4, which gives us the first point of (0, -4).

We can find the second point by using the numerator of the slope to determine how much we go up or down (-3) and the denominator for how much we go left to right (4). So we add the 4 to the x value and add the -3 to the y value.

(4, -7)

3 0

3 years ago