Answer:
4c² + 11cd + 5d
Step-by-step explanation:
To add monomials, you have to look at the variables that are accompanied by their coefficients. In the given problem, (–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd), you can combine both cd ut nt cd and c² and cd and d and d and c² because they have different variables.
(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd)
(-4c² + 8c²) + (7cd + 4cd) + (8d - 3d)
4c² + 11cd + 5d
P = 4x + 2y
additional info.
<span>x+2y <u><</u> 10
y <u><</u> 2
x <u>></u> 0
y <u>></u> 0
y can only be 0, 1, and 2.
x + 2(0) <u><</u> 10 = x <u><</u> 10
x + 2(1) <u><</u> 10 = x + 3 <u><</u> 10 = x <u><</u> 10 - 3 = x <u><</u> 7
x + 2(2) <u><</u> 10 = x + 4 <u><</u> 10 = x < 10 - 4 = x <u><</u> 6
x = 10 ; y = 0 : P = 4(10) + 2(0) = 40 + 0 = 40
x = 7 ; y = 1 : P = 4(7) + 2(1) = 28 + 2 = 30
x = 6 ; y = 2 : P = 4(6) + 2(2) = 24 + 4 = 28
The maximum value of P is 40. Where x is 10 and y is 0.</span>
Answer:
We know that lines <em>l</em><em> </em>and <em>m</em><em> </em>are parallel. The alternate interior angles rule states that the alternate interior angles formed by parallel lines are equal. So let's equate them.
2x + 22 = 4x
putting variables on one side,
22 = 4x - 2x
Thus 2x = 22
x becomes 22÷2
Therefore,<u> x = 11.</u>
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