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Luba_88 [7]
3 years ago
5

5 language books, 6 math books. in how many ways can one math book and one language book be paired?

Mathematics
1 answer:
gulaghasi [49]3 years ago
5 0
Subtract 6 and 5. The result will be 1, which will remove 1 book to which has more numbers. 6 Math books, you take one and they are 55 language books5 books of mathematics.If in the problem tells you that you should not remove any book ... well idk lol 
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Tomas makes balloon sculpture at a circus. In 180 minutes he uses 252 balloons to make balloon sculptures. How many minutes does
Mademuasel [1]

Answer:

0.714 mins

Step-by-step explanation:

by using the rule of three:

180 mins----->252 ballons

x----------------1 ballon=0.714 mins

4 0
2 years ago
Simplify the expression (7-(-1))2+(-2)
erastova [34]
The simplified version of this equation is 8
8 0
2 years ago
Read 2 more answers
Plz help me with my Qustion
Mashutka [201]

Answer:

the answer is about 17.6

6 0
2 years ago
Read 2 more answers
"What is the probability that in 10 dice throws, you will throw AT LEAST two ‘3’s on the dice? Assume you’re throwing a single d
dem82 [27]

Answer:

There is a 51.61% probability that in 10 dice throws, you will throw AT LEAST two ‘3’s on the dice.

Step-by-step explanation:

For each throw, there are only two possible outcomes. Either it is a '3', or it is not. This means that we solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

There are 6 possible outcomes for the dice. This means that the probability that it is a '3' is \frac{1}{6} = 0.167

There are 10 throws, so n = 10.

Probability of throwing AT LEAST two ‘3’s on the dice?

Either you throw less than two, or you throw at least two. The sum of the probabilities of these events is 1. So

P(X < 2) + P(X \geq 2) = 1

P(X \geq 2) = 1 - P(X < 2).

In which

P(X < 2) = P(X = 0) + P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.167)^{0}.(0.833)^{10} = 0.1609

P(X = 1) = C_{10,1}.(0.167)^{1}.(0.833)^{9} = 0.3225

So

P(X < 2) = P(X = 0) + P(X = 1) = 0.1609 + 0.3225 = 0.4834.

Finally:

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.4839 = 0.5161.

There is a 51.61% probability that in 10 dice throws, you will throw AT LEAST two ‘3’s on the dice.

5 0
3 years ago
Complete the equation of the line through<br> (-6, -5) and (-4,-4).<br> Use exact numbers.
Nutka1998 [239]

Answer:

y = \frac{1}{2} x - 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 6, - 5) and (x₂, y₂ ) = (- 4, - 4)

m = \frac{-4+5}{-4+6} = \frac{1}{2}, thus

y = \frac{1}{2} x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (- 6, - 5), then

- 5 = - 3 + c ⇒ c = - 5 + 3 = - 2

y = \frac{1}{2} x - 2 ← equation of line

7 0
2 years ago
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