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2 years ago

9

Cooper is ordering a cheeseburger for lunch. There are 3 cheese and 5 buns to choose from. How many different hamburger can coop

er order if he makes exactly one selection for each option?

1 answer:

Alik [6]2 years ago

3 0

Answer: 15

Step-by-step explanation: u multiply

You might be interested in

Bro i need this <br><br> (x − 5)^2 = x^2 − 25

forsale [732]

Answer:

x=5

Step-by-step explanation:

x^2+25-10x = x^2-25

-x^2 -x^2

25-10x = -25

-25 -25

-10x = -50

x=5

lets check

(5-5)^2 = 5^2-25

0^2 = 25-25

0 = 0

7 0

2 years ago

Read 2 more answers

Phoenix [80]

Answer:

4

Step-by-step explanation:

If you increase the scale factor by 4, the sides become:

L= 2×4 = 8

W= 3×4 = 12

Now to find the new area:

<u>8 × 12</u> = 96cm^2

<u>So, a scale factor of </u><u>4</u> would give the rectangle a scale factor of <u>96</u>.

<u>Hope this helps and have a nice day!</u>

4 0

3 years ago

What is the measure of an interior angle of a regular 12-gon?

gavmur [86]

Answer:

The measure of an interior angle of a regular 12-gon is 150°.

Hence, option 'C' is correct.

Step-by-step explanation:

We need to determine the measure of an interior angle of a regular 12-gon.

We know that the number of sides in a regular 12-gon = n = 12

Thus,

Using the formula to determine the measure of an interior angle of a regular 12-gon is given by

(n - 2) × 180° = n × interior angle

substitute n = 12

(12 - 2) × 180 = 12 × interior angle

10 × 180 = 12 × interior angle

Interior angle = (10 × 180) / 12

= 1800 / 12

= 150°

Therefore, the measure of an interior angle of a regular 12-gon is 150°.

Hence, option 'C' is correct.

4 0

3 years ago

In a recent year, a poll asked 2362 random adult citizens of a large country how they rated economic conditions. In the poll,

Harman [31]

Answer:

a) The 99% confidence interval is given by (0.198;0.242).

b) Based on the p value obtained and using the significance level assumed $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we fail to reject the null hypothesis, and we can said that at 1% of significance the proportion of people who are rated with Excellent/Good economy conditions not differs from 0.24. The interval also confirms the conclusion since 0.24 it's inside of the interval calculated.

c) $\alpha=0.01$

Step-by-step explanation:

<em>Data given and notation </em>

n=2362 represent the random sample taken

X represent the people who says that they would watch one of the television shows.

$\hat p=\frac{X}{n}=0.22$ estimated proportion of people rated as Excellent/Good economic conditions.

$p_o=0.24$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest) <em> </em>

<em>Concepts and formulas to use </em>

We need to conduct a hypothesis in order to test the claim that 24% of people are rated with good economic conditions:

Null hypothesis: $p=0.24$

Alternative hypothesis: $p \neq 0.24$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Part a: Test the hypothesis

<em>Check for the assumptions that he sample must satisfy in order to apply the test </em>

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.

b) The sample needs to be large enough

np = 2362x0.22=519.64>10 and n(1-p)=2364*(1-0.22)=1843.92>10

Condition satisfied.

<em>Calculate the statistic</em>

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.22 -0.24}{\sqrt{\frac{0.24(1-0.24)}{2362}}}=-2.28$

The confidence interval would be given by:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

The critical value using $\alpha=0.01$ and $\alpha/2 =0.005$ would be $z_{\alpha/2}=2.58$ . Replacing the values given we have:

$0.22 - (2.58)\sqrt{\frac{0.22(1-0.22)}{2362}}=0.198$

$0.22 + (2.58)\sqrt{\frac{0.22(1-0.22)}{2362}}=0.242$

So the 99% confidence interval is given by (0.198;0.242).

Part b

<em>Statistical decision </em>

P value method or p value approach . "This method consists on determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided is $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

So based on the p value obtained and using the significance level assumed $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we fail to reject the null hypothesis, and we can said that at 1% of significance the proportion of people who are rated with Excellent/Good economy conditions not differs from 0.24. The interval also confirms the conclusion since 0.24 it's inside of the interval calculated.

Part c

The confidence level assumed was 99%, so then the signficance is given by $\alpha=1-confidence=1-0.99=0.01$

6 0

3 years ago

Which of the following pairs of numbers contains like fractions?

Harrizon [31]

Answer:

D

Step-by-step explanation:

if you multiply 5 by 2 you get 10

if you multiply 6 by 2 you get 12

5/2 (2) =10/12

Hope this helped

:)

4 0

3 years ago

Read 2 more answers