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3 years ago

I need help with this math problem and how you solved it...

Mathematics

2 answers:

Galina-37 [17]3 years ago

8 0

To get angle Y, you have to do 90 - 27 to get the other angle in the triangle and you get 63. Then you do 180 - (63+51) which is 66.

Angle Y = 66

Anit [1.1K]3 years ago

7 0

90 - 27 = 63 We can do this step because there is a right angle and it's supplement must equal 90° as well.

63 + 51 + y = 180 Triangle Sum Theorum (All sides of a Δ = 180°)

112 + y = 180 Subtract 112 on both sides.
-112 - 112
----------------------
y = 68 Final Answer

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What’s the answer to this

Ipatiy [6.2K]

2.4/0.3=8
0.3x8=2.4
The scale factor is 8.

7 0

3 years ago

On a number line, point D is at -3, and point E is at 6. The point F lies on DE. The ratio of DF to FE is 2:3. Where does point

expeople1 [14]

Answer: point F is at <u> 0.6 </u> on the number line

=============================================================

Explanation:

The ratio 2:3 scales up to 2x:3x for some positive real number x.

This means the distance from D to F is 2x units, and the distance from F to E is 3x units. Combine those two smaller distances to get 2x+3x = 5x to represent the full distance from D to E.

D is at -3 and E is at 6. This is a distance of 9 units since |-3-6| = |-9| = 9

Set this equal to the 5x from earlier and solve

5x = 9

x = 9/5

x = 1.8

This leads to 2x = 2*1.8 = 3.6

Therefore, we'll move 3.6 units from -3 to -3+3.6 = 0.6 which is the location of point F on the number line.

Notice that from 0.6 to 6 is 5.4 units and that 3x = 3*1.8 = 5.4 matches up to help confirm the answer.

5 0

2 years ago

Can u please help me with this 2 problem please

Mice21 [21]

<h2>19.</h2><h3>Given</h3>

window width and height are in proportion to building width and height
window width and height are 11 in and 18 in, respectively
building height is 108 ft

building width

<h3>Solution</h3>

The proportional relation can be written as

... (building width)/(building height) = (window width)/(window height)

Multiplying by (building height) gives

... (building width) = (building heigh) × (window width)/(window height)

... (building width) = 108 ft × (11 in)/(18 in)

... building width = 66 ft

<h2>21.</h2><h3>Given</h3>

map distance = 6.75 in
map scale = 1.5 in : 5 mi

actual distance

<h3>Solution</h3>

The distances are in proportion, so

... (map distance) : (actual distance) = 1.5 in : 5 mi

Multiplying by (5 mi)/(1.5 in)×(actual distance), we have

... (5 mi)/(1.5 in)×(6.75 in) = (actual distance) = 22.5 mi

6 0

3 years ago

A copy machine can print 480 copies every 4 minutes. A teacher printed 720 copies. How long did it take to print?

Dafna1 [17]

Answer:

6 minutes

Step-by-step explanation:

every minute is 120

720/120=6

3 0

2 years ago

Read 2 more answers

Rajan needs 1 liter of 15% hydrochloric acid solution for an experiment. He checks his storage cabinet, but he only has a 5-lite

Delvig [45]

Answer:

<em>0.75</em><em> liters of 5% hydrochloric acid solution </em>
<em>0.25</em><em> liters of 45% hydrochloric acid solution.</em>

Step-by-step explanation:

Let us assume that, x liters of the 5% hydrochloric acid and y liters of the 45% hydrochloric acid solutions are combined.

As Rajan need total of 1 liter of solution, so

$x+y=1$

i.e $x=1-y$ --------------------1

As Rajan needs 5% hydrochloric acid and 45% hydrochloric acid to make a 1 liter batch of 15% hydrochloric acid, hence acid content of the mixture of two acids will be same as of the final one, so

$0.05x+0.45y=1\times 0.15$