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Svetach [21]
3 years ago
15

I need help with this math problem and how you solved it...

Mathematics
2 answers:
Galina-37 [17]3 years ago
8 0
To get angle Y, you have to do 90 - 27 to get the other angle in the triangle and you get 63. Then you do 180 - (63+51) which is 66. 

Angle Y = 66
Anit [1.1K]3 years ago
7 0
90 - 27 = 63      We can do this step because there is a right angle and it's                                       supplement must equal 90° as well.

63 + 51 + y = 180      Triangle Sum Theorum (All sides of a Δ = 180°)

112 + y = 180       Subtract 112 on both sides.
-112        - 112
----------------------
y = 68                         Final Answer

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0.0090 in scientific notation
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Answer: 9 x 10^{-3}

Step-by-step explanation:

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3 years ago
What is the answer for 13y-2b= 15y?
Tpy6a [65]
13y-2b=15y
2b=2y
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A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th
OlgaM077 [116]

Answer:

Interval [16.34 , 21.43]

Step-by-step explanation:

First step. <u>Calculate the mean</u>

\bar X=\frac{(23+18+23+12+13+23)}{6}=18.666

Second step. <u>Calculate the standard deviation</u>

\sigma =\sqrt{\frac{(23-18.666)^2+(18-18.666)^2+(23-18.666)^2+(12-18.666)^2+(13-18.666)^2+(23-18.666)^2}{6}}

\sigma=\sqrt\frac{18.783+0.443+18.783+44.435+5.666+18.783}{6}

\sigma=\sqrt{17.815}=4.22

As the number of data is less than 30, we must use the t-table to find the interval of confidence.

We have 6 observations, our level of confidence DF is then 6-1=5 and we want our area A to be 80% (0.08).  

We must then choose t = 1.476 (see attachment)

Now, we use the formula that gives us the end points of the required interval

\bar X \pm t\frac{\sigma}{\sqrt n}

where n is the number of observations.

The extremes of the interval are then, rounded to the nearest hundreth, 16.34 and 21.43

6 0
3 years ago
What is the equation of this parabola in vertex form
attashe74 [19]

first off, let's notice the parabola is a vertical one, therefore the squared variable is the x, and the parabola is opening upwards, meaning the coefficient of x² is positive.

let's notice the vertex, or U-turn, is at (-2, 2)

\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \boxed{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{-2}{ h},\stackrel{2}{ k}) \\\\\\ y=+1[x-(-2)]^2+2\implies y=(x+2)^2+2

6 0
3 years ago
Which graph represents y as a function of x?
Lubov Fominskaja [6]

Answer:

A

Step-by-step explanation:

By vertical line test, if you draw any vertical line, except for A, all graph meet at more than two points. So, graph A represents y as a function of x.

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3 years ago
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