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Lera25 [3.4K]
2 years ago
9

A material that does not conduct heat well can be used as __________.

Mathematics
1 answer:
victus00 [196]2 years ago
5 0
A material that doesn’t conduct well would be referred to as an insulator because it keeps the heat/electricity in.
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Salut! <br> |4x^2+9x-9|=0 <br> X= ? <br> Multumesc in avans :D
Afina-wow [57]
X=3 or -3/4.<span>Îmi pare rău că nu mi-am arătat munca</span>
8 0
3 years ago
What is the number of roots for polynomial function of f(x) = (x^2 + 6)^2
Lena [83]

Answer:

x=±√6i

Step-by-step explanation:

(x^{2} +6)^{2} =0

x^{2}+6=0

x^{2} =-6

x=±√6i

5 0
3 years ago
1. 1. 1<br>___ = ___. - ______<br>6x². 3x². x​
mrs_skeptik [129]

Answer:

hope its help brain least me

7 0
2 years ago
Liam says - (5/12) is equivalent to 5/-12. Explain if Liam is correct by completing the statements below.
makkiz [27]

A positive number divided by a positive number results in a negative quotient, and it's opposite is always positive. The fraction 5/-12 can be described as a positive number divided by a negative number, which always results in a negative quotient. The fractions have different value, so Liam is not correct.

6 0
3 years ago
Read 2 more answers
For the problem 1/5g- 1/10- g + 1 3/10g -1/10, Tyson created an equivalent expression using the following steps. 1/5g+-1g+1 3/10
professor190 [17]

The true statements are:

  • Tyson's expression is not equivalent to the original expression
  • The equivalent expression is:\frac{1}{2}g- \frac 1{5}

<h3>What are equivalent expressions?</h3>

Equivalent expressions are expressions that have equal values

The original expression is given as:

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10}

Collect like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac 15g - g + 1 \frac{3}{10}g- \frac 1{10}  -\frac{1}{10}

Evaluate the like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac{1}{2}g- \frac 1{5}

Tyler's equivalent expression is given as:

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10}

Collect like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = \frac15g-g+ 1 \frac3{10}g-\frac 45g-\frac 1{10}+1 \frac{1}{10}

Evaluate the like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = -\frac 3{10}g

The simplified expressions of the original expression, and Tyson's equivalent expressions are not equal.

Hence, Tyson's expression is not equivalent to the original expression

Read more about equivalent expressions at:

brainly.com/question/9603710

3 0
2 years ago
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