Determine which function has a range of {y∣y≤3}. f f(x)=-2x−3 g f(x)=-2|x+3|−3 h f(x)=-2(x−4)2+3 j f(x)=-2x3+3x2+x−1
1 answer:
See the attached figure.
<span>f(x)=-2x−3 ⇒⇒ black graph ⇒⇒ range = R
</span>
<span>g(x)=-2|x+3|−3 ⇒⇒ red graph ⇒⇒ range = </span><span>{y∣y ≤ -3}
</span>
<span>h(x)=-2(x−4)²+3 ⇒⇒ blue graph ⇒⇒ </span><span>range = {y∣y ≤ 3}
</span>
<span>j(x)=-2x³+3x²+x−1 ⇒⇒ green graph </span>⇒⇒ range = R
∴ <span>The function which has a range of {y∣y ≤ 3} is </span><span>h(x)=-2(x−4)²+3
</span>
<span></span> Which is the third choice
<span></span>
<span>f(x)=-2x−3 ⇒⇒ black graph ⇒⇒ range = R
</span>
<span>g(x)=-2|x+3|−3 ⇒⇒ red graph ⇒⇒ range = </span><span>{y∣y ≤ -3}
</span>
<span>h(x)=-2(x−4)²+3 ⇒⇒ blue graph ⇒⇒ </span><span>range = {y∣y ≤ 3}
</span>
<span>j(x)=-2x³+3x²+x−1 ⇒⇒ green graph </span>⇒⇒ range = R
∴ <span>The function which has a range of {y∣y ≤ 3} is </span><span>h(x)=-2(x−4)²+3
</span>
<span></span> Which is the third choice
<span></span>
You might be interested in