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il63 [147K]
3 years ago
10

Tiya flipped a coin 40 times. the coin landed heads up 16 times and tails up 24 times. part

Mathematics
2 answers:
Marizza181 [45]3 years ago
8 0
Probability? I'm guessing it is asking for a written response so I'll try my best.

If the coin landed heads up 16 times then the probability would be 16/40 which can be reduced to 2/5 
If the coin landed tails up 24 times you would do the same so 24/40 and then you can reduce that to 3/5

Part a: The experimental probability of it being tails would be 3/5
Part b: The experimental probability of it being heads would be 2/5

hopefully, I understood the question correctly but I believe this is the right answer
Blababa [14]3 years ago
5 0

Answer:

a)  Experimental probability = 0.4

a)  Theoretical probability = 0.5

Step-by-step explanation:

Probability is the ratio of number of favorable outcome to total number of out comes.

Part a:

The experimental probability of the coin landing heads up

              Total number of outcomes = 40

              Number of favorable outcome = 16

              Experimental probability =\frac{16}{40}=0.4

Part b:

The theoretical probability of the coin landing heads up

A coin has two sides head and tail,so probability of landing heads up is 0.5.

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\bold{\huge{\green{\underline{ Solution }}}}

\bold{\underline{ Given}}

  • <u>We </u><u>have </u><u>given </u><u>that </u><u>the </u><u>coordinates </u><u>of </u><u>the </u><u>end </u><u>point </u><u>G </u><u>and </u><u>H </u><u>are </u><u>(</u><u> </u><u>-</u><u>6</u><u>,</u><u>5</u><u>)</u><u> </u><u>and </u><u>(</u><u> </u><u>2</u><u>,</u><u> </u><u>-</u><u>7</u><u> </u><u>)</u>

\bold{\underline{To  \: Find :- }}

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>length </u><u>of </u><u>GH </u>

\bold{\underline{Let's \:  Begin :- }}

The coordinates of G = ( -6 , 5 )

The coordinates of H = ( 2 , - 7 )

<u>According </u><u>to </u><u>the </u><u>distance </u><u>formula</u><u>, </u><u> </u><u>we </u><u>get </u><u>:</u><u>-</u><u> </u>

\purple{\bigstar}\boxed{\sf{Distance\:\:GH=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2\;}}}

  • <u>Here</u><u>, </u><u> </u><u>x1</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>,</u><u> </u><u>x2</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>and </u><u>y1</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>,</u><u> </u><u>y2</u><u> </u><u>=</u><u> </u><u>-</u><u>7</u>

<u>Subsitute </u><u>the </u><u>required </u><u>values </u><u>in </u><u>the </u><u>above </u><u>formula </u>

\sf{ Distance \:GH = √( -6 - 2)² + ( 5 -(-7))²}

\sf{Distance\:GH= √(-8)^2+(5 + 7)^2}

\sf{Distance\:GH=√(-8)^2+(12)^2}

\sf{ Distance \:GH =√64 + 144 }

\sf{ Distance \:GH =√ 208}

\sf{ Distance\: GH = √ 2 × 2 × 2 × 2 × 13}

\sf{ Distance \:GH = 4√13}

\sf{\red{ Hence\: the \: length\:of \: GH \: is \: 4√13 \: units}}

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lord [1]

Answer:

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