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IrinaK [193]
3 years ago
15

Mia needs to separate 270 blue pens and 180 red pens into packs. Each pack will have the same number of blue pens and the same n

umber of red pens. What is the greatest number of packs she can make? How many red pens and how many blue pens will be in each pack?
Mathematics
2 answers:
fredd [130]3 years ago
5 0
The greatest number of packs is gonna be the GCF of 180 and 270, which is 90 packs.

270/90 = 3
180/90 = 2

so Mia can make 90 packs each pack containing 3 blue pens and 2 red pens
sammy [17]3 years ago
3 0

Answer:

3 blue pens and 2 red pens in each pack.

90 packs.

Step-by-step explanation:

We have been given that Mia needs to separate 270 blue pens and 180 red pens into packs. Each pack will have the same number of blue pens and the same number of red pens.

To solve our given problem, we will find greatest common factor of 270 and 180.    

Factors of 270: 1, 2, 3, 5, 6, 9, 10, 15, 18, 27, 30, 45, 54, 90, 135, 270.

Factors of 180: 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 30, 36, 45, 60, 90, 180.

We can see that GCF of 180 and 270 is 90, therefore, Mia can make 90 packs.

\text{Blue pens in each pack}=\frac{270}{90}=3

\text{Red pens in each pack}=\frac{180}{90}=2

Therefore, there will be 3 blue pens and 2 red pens in each pack.

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