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horsena [70]
3 years ago
14

What is the remainder when the following polynomial is divided by (x+2)? f (x) = 3x^5 - 2x^3 + 4x-7

Mathematics
1 answer:
jek_recluse [69]3 years ago
4 0

Answer:

remember me?

Step-by-step explanation:

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Wat is 366-84+93×(64+100)=?<br><br><br>A) 88,777,990<br>B)1,000,7<br>C) Oof._.<br>D)490,360,92​
NemiM [27]

Answer:

Retorical question:its actually:

15,534

Step-by-step explanation:

64+100=164

164×93=15,252

366-84=282

15,252 + 282 = 15,252

6 0
3 years ago
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Tell me all the characteristics you can
labwork [276]

4 x 3+2 x 2+ x −7=0 ... 3.3 Find roots (zeroes) of : F(x) = 4x3+2x2+x-7. Polynomial Roots Calculator is a set of methods aimed at finding values of x

5 0
3 years ago
Explain how the Quotient of Powers was used to simplify this expression.
Ksju [112]
For this case we have the following expression:
 \frac{5^4}{25}
 Rewriting the expression we have:
 \frac{5^4}{5^2}
 In the division, if we have the same base, the exponents are subtracted.
 Therefore, by rewriting the expression we have:
 \frac{5^4}{5^2}=5^{4-2}
 5^{4-2} = 5^2&#10;
 Answer:
 
The equivalent expression is given by:
 
\frac{5^4}{25}=5^2
5 0
4 years ago
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Solution to 3x+5y=-20
zloy xaker [14]

3x+5y=-20

5y=-20divide

the answer is x=-4

3x=-20 divide

the answer is y=-20

3 0
3 years ago
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Can someone be so freaking awesome and help me out with the correct answer please :( !?!?!?!?!???!!! 30 points!!!
Sindrei [870]

\bf 7~~,~~\stackrel{7+6}{13}~~,~~\stackrel{13+6}{19}~~,~~\stackrel{19+6}{25}\qquad \impliedby \qquad \textit{common difference "d" is 6}

we know all it's doing is adding 6 over again to each term to get the next one, so then

\bf \stackrel{\textit{Recursive Formula}}{\stackrel{\textit{nth term}}{f(n)}~~=~~\stackrel{\textit{the term before it}}{f(n-1)}~~~~\stackrel{\textit{plus 6}}{+~~~~6}}

now for the explicit one

\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ a_1=7\\ d=6 \end{cases} \\\\\\ a_n=7+(n-1)6\implies a_n=7+6n-6\implies \stackrel{\textit{Explicit Formula}}{\stackrel{f(n)}{a_n}=6n+1} \\\\\\ therefore\qquad \qquad f(10)=6(10)+1\implies f(10)=61

3 0
3 years ago
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