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3 years ago

Select all of the potential solution(s) of the equation 2log5x=log54.

Mathematics

2 answers:

Ilya [14]3 years ago

8 0

X= -2 and x= 2 are the answers

sergij07 [2.7K]3 years ago

3 0

Given : $2log_{5} x^{2} =log_{5} 2^{2}$

To solve for x we use the logarithm rule for powers.

The log rule for powers states:

$mlog_{a}n =log_{a} n^{m}$

We apply this rule to the left side of the equation.

[tex] log_{5} x^{2} =log_{5} 4

Both sides have log with same base so it can be eliminated.

Eliminating log from both sides we have:

[tex] x^{2} =4

To solve for x we take root of both sides

x=2,-2.

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Vikentia [17]

y=9.99x+3

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y=9.99*7+3

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3 years ago

Joey bought a dozen oranges for $3.50 and several bananas for $0.25 each at the grocery store. Joey spent a total of $5.75 on th

blagie [28]

Answer:

9 bananas

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Look at this set of 8 numbers:33769234 how would the range change if the number 6 replaced the number 7 in the set

klio [65]

Put the numbers in order

2,3,3,3,4,6,7,9.....the range is the largest number minus the smallest number
so as it is, the range is (9 - 2) = 7

if u replaced the 7 with a 6...
2,3,3,3,4,6,6,9...the range is STILL (9 - 2) = 7

3 0

3 years ago

Please help me!!! Select all of the equations for which the solution is 20. A) n-4 B) 10n=20 C) n/5=4 D)7+n=13 Please wander imm

Cerrena [4.2K]

I'm guessing it is C because after you solve for n (you need to multiply the five over to isolate n), you get 20.

8 0

3 years ago

Use the fact that the mean of a geometric distribution is μ= 1 p and the variance is σ2= q p2. A daily number lottery chooses th

butalik [34]

Answer:

a). The mean = 1000

The variance = 999,000

The standard deviation = 999.4999

b). 1000 times , loss

Step-by-step explanation:

The mean of geometric distribution is given as , $\mu = \frac{1}{p}$

And the variance is given by, $\sigma ^2=\frac{q}{p^2}$

Given : $p=\frac{1}{1000}$

= 0.001

The formulae of mean and variance are :

$\mu = \frac{1}{p}$

$\sigma ^2=\frac{q}{p^2}$

$\sigma ^2=\frac{1-p}{p^2}$

a). Mean = $\mu = \frac{1}{p}$

= $\mu = \frac{1}{0.001}$

= 1000

Variance = $\sigma ^2=\frac{1-p}{p^2}$

= $\sigma ^2=\frac{1-0.001}{0.001^2}$

= 999,000

The standard deviation is determined by the root of the variance.

$\sigma = \sqrt{\sigma^2}$

= $\sqrt{999,000}$ = 999.4999

b). We expect to have play lottery 1000 times to win, because the mean in part (a) is 1000.

When we win the profit is 500 - 1 = 499

When we lose, the profit is -1

Expected value of the mean μ is the summation of a product of each of the possibility x with the probability P(x).

$\mu=\Sigma\ x\ P(x)= 499 \times 0.001+(-1) \times (1-0.001)$

= $ 0.50

Since the answer is negative, we are expected to make a loss.

4 0

3 years ago