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olganol [36]
2 years ago
9

Xavier is buying notebooks for school. The table below shows the number of notebooks he can buy and the total cost.

Mathematics
2 answers:
DochEvi [55]2 years ago
7 0

Answer:

2.41 * n = y

Step-by-step explanation:

From the table, we can notice that the value;

y/n is a constant for each of the rows

this represents the individual costs of each of the books

So, we have it that;

7.23/3 = 4.82/2 = 9.64/4 = $2.41

So, the books have a unit cost of $2.41

Hence, by multiplying the number of books n by 2.41 we can get the cost y

So mathematically, we have the relation as;

2.41 * n = y

forsale [732]2 years ago
4 0

Answer:

C

Step-by-step explanation:

C. 2.41 × n = y

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Answer:

-12

Step-by-step explanation:

When you multiply a positive by a negative, the answer is always a negative. If you multiply two negatives, the answer is always positive. If you multiply 2 positives, the answer will always be positive.

7 0
3 years ago
For a given IQ test, an individual is considered a genius if their score falls more than three standard deviations from the mean
ki77a [65]

Answer:

P(Z>3) = 1-P(Z

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a.2

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu=?,\sigma=?)  

We are interested on this probability

P(X>X+3\mu)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

And we can find the following probablity:

P(Z>3) = 1-P(Z

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a/2.0

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Step-by-step explanation:

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Step-by-step explanation:

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