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AnnZ [28]
3 years ago
6

Nita earns $20 per week walking her neighbor's dog. She also makes $2 per rose that she sells from her rose garden. Nita wants h

er weekly income to be at least $50. Create an inequality that correctly represents Nita's situation by dragging and dropping the three values into the appropriate spaces provided. x is the number of roses that Nita needs to sell.
Mathematics
2 answers:
VikaD [51]3 years ago
5 0

Answer:

15 roses

Step-by-step explanation:

20+2x≥50

-20     -20

2x≥30

2x/2≥30/2

x≥15

lyudmila [28]3 years ago
4 0

Answer:

20+2<u>></u>50

         

Step-by-step explanation:

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On Tuesday, a local hamburger shop sold a combined total of 258 hamburgers and cheeseburgers. The number of cheeseburgers sold w
choli [55]

Answer:

516

Step-by-step explanation:

Step 1:

258 × 2 = 516

Answer:

516

Hope This Helps :)

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Del ray can run 20 1/2 miles in 2 1/4 hours. How many miles per hour can he run?
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20 \frac{1}{2} :2 \frac{1}{4} = \frac{41}{2}: \frac{9}{4}=  \frac{41}{2}* \frac{4}{9} =\frac{82}{9} =  9 \frac{1}{9} \ \ \text{miles per hour}
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Six equilateral triangles are connected to create a regular hexagon. The area of the hexagon is 24a2 – 18 square units. Which is
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8 0
3 years ago
Read 2 more answers
Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a tha
const2013 [10]

Answer:

(a) The value of <em>a</em> is 53.35.

(b) The value of <em>a</em> is 38.17.

(c) The value of <em>a</em> is 26.95.

(d) The value of <em>a</em> is 25.63.

(e) The value of <em>a</em> is 12.06.

Step-by-step explanation:

The probability density function of <em>X</em> is:

f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}

Here, 22 < X < 55.

(a)

Compute the value of <em>a</em> as follows:

P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35

Thus, the value of <em>a</em> is 53.35.

(b)

Compute the value of <em>a</em> as follows:

P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17

Thus, the value of <em>a</em> is 38.17.

(c)

Compute the value of <em>a</em> as follows:

P(X\geq  a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95

Thus, the value of <em>a</em> is 26.95.

(d)

Compute the value of <em>a</em> as follows:

P(X\geq  a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63

Thus, the value of <em>a</em> is 25.63.

(e)

Compute the value of <em>a</em> as follows:

P(1.83\leq X\leq  a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06

Thus, the value of <em>a</em> is 12.06.

7 0
3 years ago
Can someone help me here ASAP? this question is worth 20 points. will mark the brainliest, thank you so much in advanced.
worty [1.4K]

Answer:

1. a) (1-1) (1-2) (1-3) (2-1) (2-2) (3-1)

2. a) (5-1) (5-2) (5-3) (5-4) (5-5) (5-6)

3. d) (1-3) (2-3) (3-1) (3-2) (3-4) (3-5) (3-6) (4-3) (5-3) (6-3)

Step-by-step explanation:

1. added the numbers in the parenthesis and A had all of the sums less than 5

2. A had all the 5s in the first spot

3. D had the  3s in each parenthesis

3 0
3 years ago
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