C ! It’s the quadratic formula hope this helps
The equation would be:

V represents video game
M represents movies
Derrick plans to spend some or all which means he can use less than that amount or the whole amount
Hope this helps.
first off, let's split the triplet into two equations, then from there on we'll do substitution.
![\cfrac{y}{x-z}=\cfrac{x}{y}=\cfrac{x+y}{z}\implies \begin{cases} \cfrac{y}{x-z}=\cfrac{x}{y}\\[2em] \cfrac{x}{y}=\cfrac{x+y}{z} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{using the 1st equation}}{\cfrac{y}{x-z}=\cfrac{x}{y}\implies }y^2=\underline{x^2-xz} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{using the 2nd equation}}{\cfrac{x}{y}=\cfrac{x+y}{z}\implies }xz=xy+y^2\implies \stackrel{\textit{substituting for }y^2}{xz=xy+(\underline{x^2-xz})}](https://tex.z-dn.net/?f=%5Ccfrac%7By%7D%7Bx-z%7D%3D%5Ccfrac%7Bx%7D%7By%7D%3D%5Ccfrac%7Bx%2By%7D%7Bz%7D%5Cimplies%20%5Cbegin%7Bcases%7D%20%5Ccfrac%7By%7D%7Bx-z%7D%3D%5Ccfrac%7Bx%7D%7By%7D%5C%5C%5B2em%5D%20%5Ccfrac%7Bx%7D%7By%7D%3D%5Ccfrac%7Bx%2By%7D%7Bz%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Busing%20the%201st%20equation%7D%7D%7B%5Ccfrac%7By%7D%7Bx-z%7D%3D%5Ccfrac%7Bx%7D%7By%7D%5Cimplies%20%7Dy%5E2%3D%5Cunderline%7Bx%5E2-xz%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Busing%20the%202nd%20equation%7D%7D%7B%5Ccfrac%7Bx%7D%7By%7D%3D%5Ccfrac%7Bx%2By%7D%7Bz%7D%5Cimplies%20%7Dxz%3Dxy%2By%5E2%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bsubstituting%20for%20%7Dy%5E2%7D%7Bxz%3Dxy%2B%28%5Cunderline%7Bx%5E2-xz%7D%29%7D)
![2xz=xy+x^2\implies 2xz=x(y+x)\implies \cfrac{2xz}{x}=y+x \\\\\\ 2z=y+x\implies 2=\cfrac{y+x}{z}\implies 2=\cfrac{x+y}{z} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{}{ \begin{cases} \cfrac{y}{x-z}=\cfrac{x}{y}\\[2em] \cfrac{x}{y}=\cfrac{x+y}{z} \end{cases}}\implies \begin{cases} \cfrac{y}{x-z}=\cfrac{x}{y}\\[2em] \cfrac{x}{y}=2 \end{cases}\implies \begin{cases} \cfrac{y}{x-z}=2\\[2em] \cfrac{x}{y}=2 \end{cases}](https://tex.z-dn.net/?f=2xz%3Dxy%2Bx%5E2%5Cimplies%202xz%3Dx%28y%2Bx%29%5Cimplies%20%5Ccfrac%7B2xz%7D%7Bx%7D%3Dy%2Bx%20%5C%5C%5C%5C%5C%5C%202z%3Dy%2Bx%5Cimplies%202%3D%5Ccfrac%7By%2Bx%7D%7Bz%7D%5Cimplies%202%3D%5Ccfrac%7Bx%2By%7D%7Bz%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%7D%7B%20%5Cbegin%7Bcases%7D%20%5Ccfrac%7By%7D%7Bx-z%7D%3D%5Ccfrac%7Bx%7D%7By%7D%5C%5C%5B2em%5D%20%5Ccfrac%7Bx%7D%7By%7D%3D%5Ccfrac%7Bx%2By%7D%7Bz%7D%20%5Cend%7Bcases%7D%7D%5Cimplies%20%5Cbegin%7Bcases%7D%20%5Ccfrac%7By%7D%7Bx-z%7D%3D%5Ccfrac%7Bx%7D%7By%7D%5C%5C%5B2em%5D%20%5Ccfrac%7Bx%7D%7By%7D%3D2%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Bcases%7D%20%5Ccfrac%7By%7D%7Bx-z%7D%3D2%5C%5C%5B2em%5D%20%5Ccfrac%7Bx%7D%7By%7D%3D2%20%5Cend%7Bcases%7D)
that of course, is only true if x + y, or our numerator doesn't turn into 0, if it does then our fraction becomes 0 and our equation goes south. Keeping in mind that x,y and z are numeric values that correlate like so.
Answer:
35
Step-by-step explanation:
by adding three to the next number each time, the answer is 35
Answer:
N+P or number 3
Step-by-step explanation: