Question

Find the distance/length of segment AB is A(2.125) and B(98, 15)

Answer 1

Answer:

146

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra I

• Coordinates (x, y)

Algebra II

• Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point A(2, 125)

Point B(98, 15)

Step 2: Identify

A(2, 125) → x₁ = 2, y₁ = 125

B(98, 15) → x₂ = 98, y₂ = 15

Step 3: Find distance d

1. Substitute in coordinates [Distance Formula]:                                               $\displaystyle d = \sqrt{(98-2)^2+(15-125)^2}$
2. [√Radical] (Parenthesis) Subtract:                                                                   $\displaystyle d = \sqrt{(96)^2+(-110)^2}$
3. [√Radical] Evaluate exponents:                                                                       $\displaystyle d = \sqrt{9216+12100}$
4. [√Radical] Add:                                                                                                 $\displaystyle d = \sqrt{21316}$
5. [√Radical] Evaluate:                                                                                         $\displaystyle d = 146$