HELP ASAP!!

Mathematics

1 answer:

garri49 [273]2 years ago

4 0

I'm pretty sure it would be x - y + 1 = 0 because if you plug in one of the coordinates into each equation, this is the only one that works.

y - x + 1 = 0
2 - 1 + 1 = 0
2 = 0 not correct

x - y + 1 = 0
1 - 2 + 1 = 0
0 = 0 correct

-x - y + 1 = 0
-1 - 2 + 1 = 0
-2 = 0 not correct

You might be interested in

2 Vishal is training for a race. His goal is to run 5.5 miles over three days. The distances he ran each day are shown in the ta

yawa3891 [41]

Answer:

Which table?

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Given: △ACM, m∠C=90°, CP ⊥ AM

larisa86 [58]

Answer: The answer is $3\dfrac{4}{7}.$

Step-by-step explanation: Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

$AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.$

Now,

$AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)$

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

$CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)$