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soldi70 [24.7K]
3 years ago
9

I need help please I don't understand

Mathematics
2 answers:
goblinko [34]3 years ago
8 0

Answer:

92

Step-by-step explanation:

i will give you process,

x + 48° + 40° = 180° (being angle in a triangle)

or, x + 88° = 180°

or, x = 180° - 88° = 92°

Therefore, x = 92

Copy the same process

igor_vitrenko [27]3 years ago
6 0

Answer:

57.2

Step-by-step explanation:

This is a right triangle so we can use trig ratios.

We are asked to find a side when we know a angle adjacent to that side. And we are given a side opposite of that angle. We can use Tangent to find the side length.

\tan(40)  =  \frac{48}{x}

Take the reciprocal of both sides.

\frac{1}{ \tan( 40) ) }  =  \frac{x}{ 48}

Multiply both sides by 48.

x =  \frac{1}{ \tan(40) }  \times 48

x = 57.2

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1. c; 2. d

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8 0
2 years ago
The lengths of brook trout caught in a certain Colorado stream are normally distributed with a mean of 14 inches and a standard
mezya [45]

Answer:

0.6563 or 65.63% of brook trout caught will be between 12 and 18 inches

Step-by-step explanation:

Mean trout length (μ) = 14 inches

Standard deviation (σ) = 3 inches

The z-score for any given trout length 'X' is defined as:  

z=\frac{X-\mu}{\sigma}  e interval

For a length of X =12 inches:

z=\frac{12-14}{3}\\z=-0.6667

According to a z-score table, a score of -0.6667 is equivalent to the 25.25th percentile of the distribution.

For a length of X =18 inches:

z=\frac{18-14}{3}\\z=1.333

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The proportion of trout caught between 12 and 18 inches, assuming a normal distribution, is the interval between the equivalent percentile of each length:

P(12\leq X\leq 18) = 90.88\% - 25.25\%\\P(12\leq X\leq 18) = 65.63\%

8 0
3 years ago
I need help with this please, could you explain so I can understand better please
MA_775_DIABLO [31]

Answer:

<3 and <6 is Alternate interior angles.

<4 and <5 is Alternate interior angles.

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<3 and <7 is Corresponding angles.

Hope this helps. :)

8 0
3 years ago
Write 0.8 as a fraction. A)29 B)49 C)79 D)89
fredd [130]
79 
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:)

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trapecia [35]
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4 0
3 years ago
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