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3 years ago

I need help please I don't understand

Mathematics

2 answers:

goblinko [34]3 years ago

8 0

Answer:

Step-by-step explanation:

i will give you process,

x + 48° + 40° = 180° (being angle in a triangle)

or, x + 88° = 180°

or, x = 180° - 88° = 92°

Therefore, x = 92

Copy the same process

igor_vitrenko [27]3 years ago

6 0

Answer:

57.2

Step-by-step explanation:

This is a right triangle so we can use trig ratios.

We are asked to find a side when we know a angle adjacent to that side. And we are given a side opposite of that angle. We can use Tangent to find the side length.

$\tan(40) = \frac{48}{x}$

Take the reciprocal of both sides.

$\frac{1}{ \tan( 40) ) } = \frac{x}{ 48}$

Multiply both sides by 48.

$x = \frac{1}{ \tan(40) } \times 48$

$x = 57.2$

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Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.

o-na [289]

Answer: $\text{Length of AG=}\frac{2\sqrt{63}}{3}$

Explanation:

Please follow the diagram in attachment.

As we know median from vertex C to hypotenuse is CM

$\therefore CM=\frac{1}{2}AB$

We are given length of CG=4

Median divide by centroid 2:1

CG:GM=2:1

Where, CG=4

$\therefore GM=2$ ft

Length of CM=4+2= 6 ft

$\therefore CM=\frac{1}{2}AB\Rightarrow AB=12$

In $\triangle ABC, \angle C=90^0$

Using trigonometry ratio identities

$AC=AB\sin 30^0\Rightarrow AC=6$ ft

$BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3}$ ft

$CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3}$ ft

In $\triangle CAN, \angle C=90^0$

Using pythagoreous theorem

$AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}$

Length of AG=2/3 AN

$\text{Length of AG=}\frac{2\sqrt{63}}{3}$ ft

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3 years ago

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Gnom [1K]

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