The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Let w represent the width, hence:
length = w + 33, height = w - 13
Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w
V(w) = w³ + 20w² - 429w
Rate of change = dV/dw = 3w² + 40w - 429
When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423
When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118
Rate = 10118 - 5423 = 4695 in³/in
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
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I can not see the picture so i caN NOT HELP SORRY
Answer:
9 3/8 ÷ 2 1/4
Step-by-step explanation:
too lazy too do it, plus if ur having a hard time doing fractions on a calc, just do 1÷4 as a replacement for .25 when shown 1/4. just go to frac calc in the future it makes it easy ro use....
Answer:
i need points lol
Step-by-step explanation:
sorryyyyy
The ordered pair which makes both inequalities true is (-2, 2).
It is given that inequalities are
y < -x + 1 and y > x
For y < -x + 1
Substituting every ordered pair,
1) (-3, 5)
⇒ 5 < - (-3) + 1
⇒ 5 < 3 + 1
⇒ 5 < 4 is false
2) (-2, 2)
⇒ 2 < -(-2) + 1
⇒ 2 < 2 + 1
⇒ 2 < 3 is true
3) (-1, -3)
⇒ -3 < - (-1) + 1
⇒ -3 < 1 + 1
⇒ -3 < 2 is true
4) (0, -1)
⇒ -1 < -0 + 1
⇒ -1 < 1 is true
Now , for y > x
1) (-3, 5)
⇒ 5 > -3 is true
2) (-2, 2)
⇒ 2 > -2 is true
3) (-1, -3)
⇒ -3 > -1 is false
4) (0, -1)
⇒ -1 > 0 is false
Therefore ,the ordered pair which makes both inequalities true is (-2, 2).
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