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2 years ago

Can someone please help me and explain?

Mathematics

1 answer:

Aleks [24]2 years ago

7 0

Have a nice day hope this helps

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Please help me with this question!

BigorU [14]

The answer is 8.8

You have to use SohCahToa to figure out the length of AB

3 0

2 years ago

What is 3-8 + 2v- v equal to?

Anettt [7]

If the answer is supposed to be an equation, it should be -5(+)v

6 0

3 years ago

Point P is the interior of LaTeX: \angle OZQ.\:∠ O Z Q .If LaTeX: m\:\angle\:OZQ\:m ∠ O Z Q= 125 and LaTeX: m\angle OZP\:m ∠ O Z

saw5 [17]

Answer:

Step-by-step explanation:

If point P is the interior of ∠OZQ , then the mathematical operation is true;

∠OZP + ∠PZQ = ∠OZQ

Given parameters

∠OZQ = 125°

∠OZP = 62°

Required

∠PZQ

TO get ∠PZQ, we will substitute the given parameters into the expression above as shown

∠OZP + ∠PZQ = ∠OZQ

62° + ∠PZQ = 125°

subtract 62° from both sides

62° + ∠PZQ - 62° = 125° - 62°

∠PZQ = 125° - 62°

∠PZQ = 63°

<em>Hence the value of ∠PZQ is 63°</em>

6 0

2 years ago

Need answer please help no links

babymother [125]

The answer is 5 feet I think

8 0

2 years ago

Q6: Which is the graph of the polar equation r=1/1-sin theta.

AveGali [126]

Answer:

The correct answer is C.

Step-by-step explanation:

The given equation is;

$r=\frac{1}{1-\sin(\theta)}$

This implies that;

$r(1-\sin(\theta)=1$

$r-r\sin(\theta)=1$

Let us write in Cartesian coordinates by substituting;

$r=\sqrt{x^2+y^2} ,y=r\sin(\theta)$

$\sqrt{x^2+y^2}-y=1$

$\sqrt{x^2+y^2}=y+1$

Square both sides;

$(\sqrt{x^2+y^2})^2=(y+1)^2$

This implies that;

$x^2+y^2=y^2+2y+1$

$x^2=2y+1$

$y=\frac{1}{2}x^2-\frac{1}{2}$

This is an equation of a parabola that opens upwards with a y-intercept of $-\frac{1}{2}$ .

The correct choice is C

4 0

2 years ago