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malfutka [58]
3 years ago
8

How many liters are in 120 kiloliters

Mathematics
2 answers:
Natali [406]3 years ago
8 0
6 is your answer, hope it helped
Len [333]3 years ago
5 0
You'll get 120,000 liters


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547321 rounded to nearest one thousand
Sphinxa [80]
The nearest thousand is 547,000
5 0
3 years ago
4(x-6)&lt;-2x+6 what is the solution to the inequality <br> _
Cloud [144]
Simplify both sides if needed. The left-hand side needs simplification.

4(x - 6) \leq -2x + 6
4x - 24 \leq  -2x + 6

All is left to do is add and subtract to get the x variable all alone.

4x - 24  \leq -2x + 6
6x - 24  \leq  6    <-- Add 2x to both sides
6x         \leq  30  <-- Add 24 to both sides 
x           \leq 5    <-- Divide both sides by 6

In order to be in the solution set, x has to be less than or equal to 5.

In interval notation: [5, -∞)
7 0
3 years ago
(a) The function k is defined by k(x)=f(x)g(x). Find k′(0).
Brut [27]

Answer:

(a) k'(0) = f'(0)g(0) + f(0)g'(0)

(b) m'(5) = \frac{f'(5)g(5) - f(5)g'(5)}{2g^{2}(5) }

Step-by-step explanation:

(a) Since k(x) is a function of two functions f(x) and g(x) [ k(x)=f(x)g(x) ], so for differentiating k(x) we need to use <u>product rule</u>,i.e., \frac{\mathrm{d} [f(x)\times g(x)]}{\mathrm{d} x}=\frac{\mathrm{d} f(x)}{\mathrm{d} x}\times g(x) + f(x)\times\frac{\mathrm{d} g(x)}{\mathrm{d} x}

this will give <em>k'(x)=f'(x)g(x) + f(x)g'(x)</em>

on substituting the value x=0, we will get the value of k'(0)

{for expressing the value in terms of numbers first we need to know the value of f(0), g(0), f'(0) and g'(0) in terms of numbers}{If f(0)=0 and g(0)=0, and f'(0) and g'(0) exists then k'(0)=0}

(b) m(x) is a function of two functions f(x) and g(x) [ m(x)=\frac{1}{2}\times\frac{f(x)}{g(x)} ]. Since m(x) has a function g(x) in the denominator so we need to use <u>division rule</u> to differentiate m(x). Division rule is as follows : \frac{\mathrm{d} \frac{f(x)}{g(x)}}{\mathrm{d} x}=\frac{\frac{\mathrm{d} f(x)}{\mathrm{d} x}\times g(x) + f(x)\times\frac{\mathrm{d} g(x)}{\mathrm{d} x}}{g^{2}(x)}

this will give <em>m'(x) = \frac{1}{2}\times\frac{f'(x)g(x) - f(x)g'(x)}{g^{2}(x) }</em>

on substituting the value x=5, we will get the value of m'(5).

{for expressing the value in terms of numbers first we need to know the value of f(5), g(5), f'(5) and g'(5) in terms of numbers}

{NOTE : in m(x), g(x) ≠ 0 for all x in domain to make m(x) defined and even m'(x) }

{ NOTE : \frac{\mathrm{d} f(x)}{\mathrm{d} x}=f'(x) }

4 0
3 years ago
Someone please help me with this
Lynna [10]

Answer:

Step-by-step explanation:

3/4x + -3

3 0
2 years ago
Read 2 more answers
Factorise 12u-uv please help lol
max2010maxim [7]

Answer:

u(12-v)

Step-by-step explanation:

12u and -uv both have a factor of <em>u </em>in common, so we can pull it out to give us the factored expression u(12-v).

<em>Note on factoring:</em>

<em>Remember, it's just using the distributive property in reverse! We can get our original expression back by distributing the u to the 12 and the -v.</em>

6 0
3 years ago
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