1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vadim26 [7]
3 years ago
14

Https://www.bing.com/videos/search?q=dancing+aaron+smith+1+hour&view=detail&mid=C6C28AF3C0CEC1E4AEE3C6C28AF3C0CEC1E4AEE3

&FORM=VIRE
enjoy.
Computers and Technology
1 answer:
Soloha48 [4]3 years ago
5 0
I’m scared bye I’m gonna copy link and see
You might be interested in
Write a static method middleValue that takes three int parameters, and returns a int . It should return the middle value of the
anygoal [31]

We use if-else structure to check the each possible scenario and return the median accordingly in the middleValue() method. The main is also provided so that you can test the method.

Comments are used to explain the each line.

You may see the output in the attachment.

public class Main

{

public static void main(String[] args) {

   

    //call the method for different scenarios

    System.out.println(middleValue(1, 2, 3));

    System.out.println(middleValue(1, 3, 2));

    System.out.println(middleValue(2, 1, 3));

    System.out.println(middleValue(2, 3, 1));

    System.out.println(middleValue(3, 1, 2));

    System.out.println(middleValue(3, 2, 1));

 

}

       //method that takes three int and returns an int

public static int middleValue(int n1, int n2, int n3) {

    //set the median as n1

    int median = n1;

   

    //check the situation where the n1 is the highest

    //if n2 is greater than n2 -> n1 > n2 > n3

    //if not -> n1 > n3 > n2

    if(n1 > n2 && n1 > n3){

        if(n2 > n3)

            median = n2;

        else

            median = n3;

    }

   

    //check the situation where the n2 is the highest

    //if n3 is greater than n1 -> n2 > n3 > n1

    //if not -> n2 > n1 > n3

    //note that we set the median as n1 by default, that is why there is no else part

    else if(n2 > n1 && n2 > n3){

        if(n3 > n1)

            median = n3;

    }

   

    //otherwise, n3 is the highest

    //if n2 is greater than n1 -> n3 > n2 > n1

    //if not -> n3 > n1 > n2

    //note that we set the median as n1 by default, that is why there is no else part

    else{

        if(n2 > n1)

            median = n2;

    }

   

    return median;

}

}

You may see another if-else question at:

brainly.com/question/13428325

6 0
3 years ago
Given an array as follows
slava [35]

Answer:

1) Method calcTotal:

  1. public static long calcTotal(long [][] arr2D){
  2.        long total = 0;
  3.        
  4.        for(int i = 0; i < arr2D.length; i++ )
  5.        {
  6.            for(int j = 0; j < arr2D[i].length; j++)
  7.            {
  8.                total = total + arr2D[i][j];
  9.            }
  10.        }
  11.        
  12.        return total;
  13.    }

Explanation:

Line 1: Define a public method <em>calcTotal</em> and this method accept a two-dimensional array

Line 2: Declare a variable, total, and initialize it with zero.

Line 4: An outer for-loop to iterate through every rows of the two-dimensional array

Line 6: An inner  for-loop to iterate though every columns within a particular row.

Line 8: Within the inner for-loop, use current row and column index, i and j, to repeatedly extract the value of each element in the array and add it to the variable total.

Line 12: Return the final total of all the element values as an output

Answer:

2) Method calcAverage:

  1. public static double calcAverage(long [][] arr2D){
  2.        double total = 0;
  3.        int count = 0;
  4.        
  5.        for(int i = 0; i < arr2D.length; i++ )
  6.        {
  7.            for(int j = 0; j < arr2D[i].length; j++)
  8.            {
  9.                total = total + arr2D[i][j];
  10.                count++;
  11.            }
  12.            
  13.        }
  14.        
  15.        double average = total / count;
  16.        
  17.        return average;
  18.    }

Explanation:

The code in method <em>calcAverage</em> is quite similar to method <em>calcTotal</em>. We just need to add a counter and use that counter as a divisor of total values to obtain an average.

Line 4: Declare a variable, count, as an counter and initialize it to zero.

Line 11: Whenever an element of the 2D array is added to the total, the count is incremented by one. By doing so, we can get the total number of elements that exist in the array.

Line 16: Use the count as a divisor to the total to get average

Line 18: Return the average of all the values in the array as an output.

Answer:

3) calcRowAverage:

  1. public static double calcRowAverage(long [][] arr2D, int row){
  2.        double total = 0;
  3.        int count = 0;
  4.        
  5.        for(int i = 0; i < arr2D.length; i++ )
  6.        {
  7.            if(i == row)
  8.            {
  9.                for(int j = 0; j < arr2D[i].length; j++)
  10.                {
  11.                    total = total + arr2D[i][j];
  12.                    count++;
  13.                }
  14.            }
  15.            
  16.        }
  17.        
  18.        double average = total / count;
  19.        
  20.        return average;
  21.    }

Explanation:

By using method <em>calcAverage </em>as a foundation, add one more parameter, row, in the method <em>calcRowAverage</em>. The row number is used as an conditional checking criteria to ensure only that particular row of elements will be summed up and divided by the counter to get an average of that row.

Line 1: Add one more parameter, row,

Line 8-15: Check if current row index, i, is equal to the target row number, proceed to sum up the array element in that particular row and increment the counter.

5 0
3 years ago
Hello brainly users can someone help me out with this question thanks!!!
slavikrds [6]

Answer:

a medical journal/study from a licenced doctor on a website with .org

Explanation:

most medical journals from licenced doctors have .org in the end and are trusted

6 0
3 years ago
Read 2 more answers
What is the typical relationship between time and interest rate?
prisoha [69]
The relationship between time and interest is: time allowed to repay the loan (monthly payments)
7 0
3 years ago
Please name the OOP term that allows children classes to have methods with the same names as methods in their parents.
RSB [31]

Answer:

Inheritance

Explanation:

3 0
3 years ago
Other questions:
  • Presentation guidelines state that slides should have no more than bullet points.
    9·2 answers
  • Which statement about tuition is the most accurate?
    11·2 answers
  • Write a program that will use user input. The program should be called PrintNumberToWordie which prints "ONE", "TWO",..., "FIVE"
    9·1 answer
  • Which of the following could be true of two diffrent speicies that have competitieve realtionship in the same ecosytem?
    10·1 answer
  • ___________ is a task pane used to correct grammar errors; opens when you click the Spelling &amp; Grammar button in the Proofin
    15·2 answers
  • Community gardens are public gardens where local residents can grow plants in a plot. They are very popular, so there are often
    7·1 answer
  • Example of negative body language include all but
    8·1 answer
  • Why does a print document need a higher raster effect setting ?​
    14·1 answer
  • What concerns exist wherever personally identifiable information is collected stored in digital form or otherwise
    10·1 answer
  • After 4th collision in ethernet, find the maximum time that the adapter waits until sensing the channel again for a 100 mbps bro
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!