Answer:
See the code below and the algorithm explanation on the figure.
Explanation:
The explanation in order to get the answer is given on the figure below.
Solving this problem with C. The program is given below:
#include <stdio.h>
int main(void) {
int n, Even=0, Odd=0, Zeros=0;
for (;;) {
printf("\nEnter the value the value that you want to check(remember just integers): ");
//IF we input a non-numeric character the code end;
if (scanf("%d", &n) != 1) break;
if (n == 0) {
Zeros++;
}
else {
if (n % 2) {
Even++;
}
else {
Odd++;
}
}
}
printf("for this case we have %d even, %d odd, and %d zero values.", Even, Odd, Zeros);
return 0;
}
The two devices in a computer that should be considered "black boxes," and should never be opened due to risks involving charged capacitors are MONITOR and POWER SUPPLY.
Explanation:
- Physical contact or close proximity to the open power supply caused a discharge from the capacitor that resulted in an electric shock. Capacitors can discharge current even when not energized because they hold a charge for some time after the power is turned off.
- To do harm to your body, the voltage across the capacitor's terminals must be high enough to cause a harmful effect on you. There are no hard rules for at what voltage things become harmful, but a common 'rule of thumb' is that DC up to 48 Volt is considered low voltage. So a capacitor charged to a voltage below 48 V is fairly safe.
- A charged capacitor can be very dangerous, so it's important that you avoid coming into contact with the terminals at all times.
plug it into a charger the go to I tunes and it should be there
The answer is Jointly.
<span>No hardware and software cannot work without each other.
</span>
Example:
<span>without a monitor, how can u install a software?</span>
