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Savatey [412]
3 years ago
5

Help if correct will give you brainliest

Mathematics
1 answer:
Scilla [17]3 years ago
8 0

Answer:

a makes sense to me

Step-by-step explanation:

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This is a continuous set of points in the coordinate plane. It can be, but is not always, straight.
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Linear. While all linear equations produce straight lines when graphed, not all linear equations produce linear functions. In order to be a linear function, a graph must be both linear (a straight line) and a function (matching each x-value to only one y-value).

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Jason wants to use all the given digits below to form a 6-digit number which is 872000 when rounded to the nearest thousand. how
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4,3,8 I think idkkkkk
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Surface integrals using an explicit description. Evaluate the surface integral \iint_{S}^{}f(x,y,z)dS using an explicit represen
Jobisdone [24]

Parameterize S by the vector function

\vec r(x,y)=x\,\vec\imath+y\,\vec\jmath+f(x,y)\,\vec k

so that the normal vector to S is given by

\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=\left(\vec\imath+\dfrac{\partial f}{\partial x}\,\vec k\right)\times\left(\vec\jmath+\dfrac{\partial f}{\partial y}\,\vec k\right)=-\dfrac{\partial f}{\partial x}\vec\imath-\dfrac{\partial f}{\partial y}\vec\jmath+\vec k

with magnitude

\left\|\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}\right\|=\sqrt{\left(\dfrac{\partial f}{\partial x}\right)^2+\left(\dfrac{\partial f}{\partial y}\right)^2+1}

In this case, the normal vector is

\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=-\dfrac{\partial(8-x-2y)}{\partial x}\,\vec\imath-\dfrac{\partial(8-x-2y)}{\partial y}\,\vec\jmath+\vec k=\vec\imath+2\,\vec\jmath+\vec k

with magnitude \sqrt{1^2+2^2+1^2}=\sqrt6. The integral of f(x,y,z)=e^z over S is then

\displaystyle\iint_Se^z\,\mathrm d\Sigma=\sqrt6\iint_Te^{8-x-2y}\,\mathrm dy\,\mathrm dx

where T is the region in the x,y plane over which S is defined. In this case, it's the triangle in the plane z=0 which we can capture with 0\le x\le8 and 0\le y\le\frac{8-x}2, so that we have

\displaystyle\sqrt6\iint_Te^{8-x-2y}\,\mathrm dx\,\mathrm dy=\sqrt6\int_0^8\int_0^{(8-x)/2}e^{8-x-2y}\,\mathrm dy\,\mathrm dx=\boxed{\sqrt{\frac32}(e^8-9)}

5 0
3 years ago
What is the reciprocal of c^2 + 8<br><br> please help!!
Serga [27]

Answer:

the answer is the same.....

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URGENT!!!!
miskamm [114]

Step-by-step explanation: What they mean is if you were to say put all that data onto a graph, any kind of graph. What graph would you chose, and why? How you would work through this kind of problem, or at least how I would approach it weight out the pros and cons of each graph, or put some data on different graphs and see what works best. On the contrary if you have a rough idea of how each graph would look like you would just chose the one you think conveys the information best. I think they're is a best answer, but no wrong answer, you can make an argument for most graphs if you try, so just chose the one you think is best, and write your reasoning.

7 0
2 years ago
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