Answer:
tan20.tan35.tan45.tan55.tan70 =1
Step-by-step explanation:
tan20.tan35.tan45.tan55.tan70
=tan(90-70) . tan(90-55) . tan45 .tan55. tan70
[we know, tan(90-θ)=cotθ]
=cot70 . cot55 . tan45 .tan55. tan70
= { tan70°.cot70°} {tan55°.cot55°}.tan45°
=1 . 1 . 1 [we know, tan∅.cot∅ = 1 & tan45°=1]
=1
pls mark as brainliest.
You don't want 'x' in the polar form. The arguments
of the sin and cos should be angles.
You're doing great. You're already through the tough part.
You knew that x = r cos(α) and y = r sin(α) .
The correct equation for where you stopped is
x· y = r² · cos(α) · sin(α) = 1
You can simplify it a little if you remember the 'double-angle' equation:
sin(2α) = 2 · sin(α) · cos(α)
So cos(α) · sin(α) = (1/2) sin(2α)
and r² · cos(α) · sin(α) = 1
r² · sin(2α) = 2
The answer is: D. -1/3 !! hope that helps
Answer:
- domain: (-∞, ∞) \ (kπ+π/2 for integers k)
- range: (-∞, ∞)
Step-by-step explanation:
The tangent function is undefined at odd multiples of π/2. It can take on any value.
The domain is all real numbers except odd multiples of π/2.
The range is all real numbers.
Answer:
84.5
Step-by-step explanation:
