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2 years ago

Please help:

Mathematics

1 answer:

suter [353]2 years ago

5 0

Answer:

A. 14:8 or 7:4

B. 14:6 or 7:3

C. 6:8 or 3:4

D. 6:28 or 3:14

Step-by-step explanation:

All you have to do is put the numbers in order and sometimes you can simplify it. It's pretty self-explanatory.

Hope this helps :)

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Write an equation of the line passing through point P that is perpendicular to the given line.

katovenus [111]

Answer:

y = 1/3x + 8

Step-by-step explanation:

*perpendicular means the reciprocal slope of the given line

m = 1/3

y = 1/3x + b

*plug in points with the point-slope equation

10 = 1/3(6) + b

10 = 2 + b

b = 8

*now plug everything into the equation

y = 1/3x + 8

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2 years ago

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HELLPPPP PLEASE ASAP WILL MARK BRAINLIEST!! PLEASW AND THANK YOUUU!!!

blagie [28]

1. It is the product of a square, meaning it can be simplified to (x+10)(x+10) or (x+10)^2

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2 years ago

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Find the angle between u =the square root of 5i-8j and v =the square root of 5i+j.

fenix001 [56]

Answer:

The angle between vector $\vec{u} = 5\, \vec{i} - 8\, \vec{j}$ and $\vec{v} = 5\, \vec{i} + \, \vec{j}$ is approximately $1.21$ radians, which is equivalent to approximately $69.3^\circ$ .

Step-by-step explanation:

The angle between two vectors can be found from the ratio between:

their dot products, and
the product of their lengths.

To be precise, if $\theta$ denotes the angle between $\vec{u}$ and $\vec{v}$ (assume that $0^\circ \le \theta < 180^\circ$ or equivalently $0 \le \theta < \pi$ ,) then:

$\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ .

<h3>Dot product of the two vectors</h3>

The first component of $\vec{u}$ is $5$ and the first component of $\vec{v}$ is also

The second component of $\vec{u}$ is $(-8)$ while the second component of $\vec{v}$ is $1$ . The product of these two second components is $(-8) \times 1= (-8)$ .

The dot product of $\vec{u}$ and $\vec{v}$ will thus be:

$\begin{aligned} \vec{u} \cdot \vec{v} = 5 \times 5 + (-8) \times1 = 17 \end{aligned}$ .

<h3>Lengths of the two vectors</h3>

Apply the Pythagorean Theorem to both $\vec{u}$ and $\vec{v}$ :

$\| u \| = \sqrt{5^2 + (-8)^2} = \sqrt{89}$ .
$\| v \| = \sqrt{5^2 + 1^2} = \sqrt{26}$ .

<h3>Angle between the two vectors</h3>

Let $\theta$ represent the angle between $\vec{u}$ and $\vec{v}$ . Apply the formula $\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ to find the cosine of this angle:

$\begin{aligned} \cos(\theta)&= \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} = \frac{17}{\sqrt{89}\cdot \sqrt{26}}\end{aligned}$ .

Since $\theta$ is the angle between two vectors, its value should be between $0\; \rm radians$ and $\pi \; \rm radians$ ( $0^\circ$ and $180^\circ$ .) That is: $0 \le \theta < \pi$ and $0^\circ \le \theta < 180^\circ$ . Apply the arccosine function (the inverse of the cosine function) to find the value of $\theta$ :

$\displaystyle \cos^{-1}\left(\frac{17}{\sqrt{89}\cdot \sqrt{26}}\right) \approx 1.21 \;\rm radians \approx 69.3^\circ$ .

3 0

2 years ago

Round 3,942,588 to the nearest thousand.

olchik [2.2K]

Hey there! :D

3,942,588

The thousandths is where the 2 is.

If the number behind the 2 is 5 or greater, we round up to 3.

It is, so round up:

3,943,000 <== rounded number

I hope this helps!
~kaikers

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2 years ago

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What is 12/21 divided by 3/14

sladkih [1.3K]

To do this problem, you gotta cross-multiply. SO, $\frac{12}{21}$ multiplied by $\frac{14}{3}$

12 times 14 = 168
21 times 3 = 63
Then the final answer is $\frac{168}{3}$

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2 years ago