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Vikentia [17]
3 years ago
11

Shareenah has 2 paintings. The first painting is 1 3/8

Mathematics
1 answer:
Galina-37 [17]3 years ago
8 0

Answer:

3/4 meters

Step-by-step explanation:

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If f(x) varies directly with x and f(x)=40 when x=8, find the value of f(x) when x=2.
melamori03 [73]

f(x)=40

x=8

so if x=2 it would be 40/8 which is 5

6 0
3 years ago
Read 2 more answers
Complete the table for the given rule. Y= x+2/3
3241004551 [841]

Answer:

decimal: x0.6 or fraction: 2/3

Step-by-step explanation:

3 0
3 years ago
Which of the following is the factored form of the given equation? 6x 2 + 2x - 8 = 0 2(3x + 4)(x - 1) = 0 (6x + 1)(x - 8) = 0 2(
Lelechka [254]
The correct answer for the question that is being presented above is this one: "2(x - 1)(3x + 4) = 0." 

<span>6x 2 + 2x - 8 = 0
(2x - 2) (3x + 4) = 0
2(x - 1)(3x + 4) = 0

The correct answer for the question that is being presented above is this one: "</span><span>(x - 4)^2 = -19."</span><span>

x2 - 8x + 3 =0
x2 - 8x + 16 = -3 - 16
(x - 4)(x - 4) = -19
(x - 4)^2 = -19</span>
3 0
3 years ago
student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te
alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = \frac{1}{4}.

Thus, the probability that the student does not receive version A = 1-\frac{1}{4} = \frac{3}{4}.

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}

= (\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5

= (\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]

= (\frac{3}{4^4})[1+\frac{1}{16}]

= (\frac{3}{256})[\frac{17}{16}]

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0
3 years ago
A: What are the solutions to the quadratic equation x^2+9=0?
Nataliya [291]

Answer:

Part A)

x=-3i

x=3i

Part B)

(x+3i)(x-3i)

Step-by-step explanation:

Given:

Part A)

x^2+9=0

x^2=-9

x= √-9

x=√-1 *√9

x=± i *3

x=±3i

Part B)

x^2+9=0

x^2 - (-9)=0

x2-(3i)^2=0

(x-3i)(x+3i)=0 !

3 0
3 years ago
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