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3 years ago

Will give brainliest and add more points to your acc if good awnser Please help ASAP

Mathematics

1 answer:

joja [24]3 years ago

7 0

Hailey's mixing two different coffee blends. Represent them by x and y (in pounds). Then x + y = 5 lb, and x = 5 - y.How much puree Sum. beans are we talking about here?
0.20x +0.80y = 0.60(5 lb) Mult all 3 terms by 100 to get rid of factions:
20x + 80 y = 300. Substitute 5-y for x:
20(5-y) + 80y = 300 => 100-20y + 80y = 300 => 60y = 200, so y = 20/6 or 10/3 lb den x = 5-10/3, or x =5/3 lb
Use 5/3 lb of the first blend and 10/3 lb of the second blend to come up with 5 lb of a 60% blend.

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Geometry solve for x

gulaghasi [49]

Answer: b

Step-by-step explanation: the parallel proportionality theorem states that “if two or more parallel lines are intersected by two transversals, the parallel lines divide the transversals proportionally.” Therefore, you make a ratio and solve:

(4/2)=(6/x) and if you solve, x=3

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3 0

3 years ago

harlie invests $325 in an account that pays 8% simple interest for 15 years. Use the simple interest formula, I = P ∙ r ∙ t, to

Alina [70]

$390 is the interest will Charlie’s initial investment earn over the 15-year period. The money does Charlie have after the 15 years is $715.

Step-by-step explanation:

Harlie invests $325 in an account.

Principal, P = $325
Interest rate, r = 8% ⇒ 0.08
Number of years, t = 15

The formula to find the interest will Charlie’s initial investment earn over the 15-year period :

⇒ $I = Prt$

⇒ $325\times 0.08\times15$

⇒ $390$

Therefore, $390 is the interest will Charlie’s initial investment earn over the 15-year period.

Money Charlie has after 15 years :

It is given by the formula,

⇒ Amount = Principal + Interest.

⇒ 325 + 390

⇒ 715 dollars.

∴ The money does Charlie have after the 15 years is $715.

3 0

3 years ago

Read 2 more answers

The sides of a rhombus with angle of 60° are 6 inches. Find the area of the rhombus.

ehidna [41]

1. Check the drawing of the rhombus ABCD in the picture attached.

2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.

3. The diagonals:
i) bisect the angles so m(ODC)=60°/2=30°

ii) are perpendicular to each other, so m(DOC)=90°

4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.

5. By the pythagorean theorem, $DO= \sqrt{ DC^{2}- OC^{2} }= \sqrt{ 6^{2}- 3^{2} }=\sqrt{ 36- 9 }=\sqrt{ 27 }= \sqrt{9*3}=$
$=\sqrt{9}* \sqrt{3} =3\sqrt{3} (in)$

6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4* $\frac{DO*OC}{2}=4 \frac{3 \sqrt{3} *3}{2}$ = $=2*9 \sqrt{3}=18 \sqrt{3}$ ( $in^{2}$ )

6 0

3 years ago

Find the dimensions of an American football field. The length is 200 ft more than the width, and the perimeter is 1,040 ft. Find

natka813 [3]

Answer:

The width of the football field is 160 feet.

The length of the football field is 360 feet.

Step-by-step explanation:

Let w represent width of the football field.

We have been given that the length is 200 ft more than the width, so the length of the field would be $w+200$ .

We are also told that the perimeter is 1,040 ft. We know that football field is in form of rectangle, so perimeter of field would be 1 times the sum of length and width. We can represent this information in an equation as:

$2(w+w+200)=1040$