Set up an equation
x+58=4x+37
21=3x
x=7
Jim:
x+58
7+58
$65
Jesse:
4x+37
4(7)+37
28+37
$65
Answer:yes
Step-by-step explanation:
<BAC=<BDE
<BCA=BED
From the markings on the diagram, we can tell E is the midpoint of BC and <u>D</u> is the midpoint of AC. We can apply the <u>triangle midsegment theorem</u>: ED = ½BA. Substituting in the expressions for the lengths and solving for x, we get x = <u>5</u>. Now, since BE = x, then BC = <u>10</u>.
<h3>What is
triangle midpoint theorem?</h3>
Triangle midpoint theorem states that the line segment which joins the midpoints of two (2) sides of a triangle is parallel to the third side, and it's congruent to one-half of the third side.
By applying the triangle midpoint theorem, we can find the value of x:
ED = ½BA
x + 2 = ½(4x - 6)
2x + 4 = 4x - 6
4x - 2x = 6 + 4
2x = 10
x = 10/2
x = 5.
BC = x + x
BC = 5 + 5
BC = 10.
Read more on triangle midpoint theorem here: brainly.com/question/16047906
#SPJ1
Answer:
Arc length MK = 15.45 units (nearest hundredth)
Arc measure = 58.24°
Step-by-step explanation:
Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)
ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

where:
is the angle- A is the side adjacent the angle
- H is the hypotenuse (the side opposite the right angle)
Given:
= ∠KLM- A = LN = 8
- H = KL = 15.2



Therefore, the measure of arc MK = 58.24° (nearest hundredth)

Given:
- r = 15.2
- ∠KLM = 58.24313614°


Answer:
Triangle 1 -
(if they want simplest radical form) or 5.4 (if they want to the nearest tenth)
Triangle 2- i couldnt figure this one out- may not be true
Pythagorean Theorem is... C) true for all right triangles
Step-by-step explanation: