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Serhud [2]
3 years ago
7

Multiply the complex numbers: (1∕2 + 4i)2

Mathematics
2 answers:
rjkz [21]3 years ago
8 0

<em>[</em><em>I'm</em><em> </em><em>supposing</em><em> </em><em>that</em><em> </em><em>you</em><em> </em><em>have</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>(</em><em>1</em><em>/</em><em> </em><em>2</em><em> </em><em>+</em><em> </em><em>4i</em><em>)</em><em>²</em><em>]</em><em> </em>

Answer:

=  \frac{ - 63}{4}  + 4i

Step-by-step explanation:

we must know that

  • <em>(a + b)² = a² + b² + 2ab </em>

{( \frac{1}{2} + 4i) }^{2}  =  { (\frac{1}{2} })^{2}  +  {(4i)}^{2}  + 2 .  \frac{1}{2}   . 4i

=  \frac{1}{4}  + 16 {i}^{2}  + 4i

  • since i²= -1

= \frac{1}{4}  - 16 + 4i

=  \frac{1 - 64}{4}  + 4i

= \underline{ \frac{ - 63}{4}  + 4i}

<em>[I'm also assuming that instead of -153/4 + 4i option A says -63/ 4 + 4i.]</em>

so the answer is<u> option A.</u>

andrezito [222]3 years ago
3 0

Step-by-step explanation:

153∕4 + 8i is the correct answer

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