All categories

3 years ago

Find the domain and range of each relation. Then determine if the relation is a function. (5,0),(6,-2),(7,10),(8,-3)

Mathematics

1 answer:

leonid [27]3 years ago

3 0

Answer:

Domain: 5, 6, 7, 8

Range: 0, -2, 10, -3

The relation is a function because each x-value has its own y-value.

Step-by-step explanation:

Domain: Set of all first elements in relation

Range: Set of all second elements in relation

How to determine if the relations is a function:

1. Identify the input values.

2. Identify the output values.

3. If each input value leads to only one output value, classify the relationship as a function.

You might be interested in

An animal shelter spends $3.00 per day to care for each cat and $5.00 per day to care for each dog. Penelope noticed that the sh

gregori [183]

Answer:

x=16

Step-by-step explanation:

6 0

3 years ago

The price of an item has increased 15% since last year. However, a person can buy the item for a 25% employee discount. The empl

ANEK [815]

Answer: $200

Explanation:

The employee pays $172.50 and he got 25% employee discount.

If the cost is $100, he pays $(100 - 25) = $75.

So, employee pays =

100

⋅

172.50

= $230.00.

Again, price was increased by 15% last year. So whose cost is $100

is sold by $(100+15) = $115.

When sell price is $115, then cost price is $100. Then,

when sell price is $230, then cost price is

100

115

⋅

230

= $200.

5 0

3 years ago

Three teachers share 2 packs of paper equally.

cupoosta [38]

I believe the answer is C because each teacher would get 2 packs for the three that get paper

3 0

3 years ago

a mixture of 40 liters of paint is 25% red tint, 30% yellow tint and 45% water. 6 liters of yellow tint are added to the origina

irakobra [83]

40 liters.....30% is yellow tint
0.30(40) = 12 liters are yellow

if u add 6 liters....(12 + 6) = 18 liters are now yellow...and since u added 6 liters, ur total mixture is now 46 liters.
18/46 = 0.39 = 39% <===

5 0

3 years ago

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

3 years ago